Find the value of x iready

A used-droid dealership buys a droid for $2900 and then sells it for $4300. What is the percent increase?

Anna71 [15]

The percent increase is 48.28

Step-by-step explanation:

Given,

Purchase price of used-droid = $2900

Selling price of used=droid = $4300

Profit = Selling price - purchase price

Profit = 4300-2900 = $1400

Percent increase = $\frac{Profit}{Purchase\ price}*100$

$Percent\ increase=\frac{1400}{2900}*100\\\\Percent\ increase=\frac{140000}{2900}\\\\Percent\ increase=48.275\%$

Rounding off to nearest hundredth;

Percent increase = 48.28%

The percent increase is 48.28

Keywords: percentage, subtraction

Learn more about percentages at:

#LearnwithBrainly

8 0

3 years ago

Could mud wrestling be the cause of a rash contracted by Washington State University students in the spring of 1992? Physicians

Daniel [21]

Thank you for posting your question here at brainly. Feel free to ask more questions.

The best and most correct answer among the choices provided by the question is A. Between 0.05 and 0.01 .
 
Hope my answer would be a great help for you.

7 0

3 years ago

Read 2 more answers

Travis has a customer who wants to purchase a portable CD player for $45 at a 20% discount. What is the amount of the discount?

kherson [118]

Just do 45x0.2 then take that number off of $45 thats your answer

8 0

3 years ago

Read 2 more answers

What is the sum of 36oz and 4 pounds

Mice21 [21]

Answer B
There are 16 oz in a pound. 16(2)=32 and there are 4 oz leftover.

6 0

3 years ago

How do you solve his with working

AlexFokin [52]

Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

$\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888$

b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

$\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884$

7 0

3 years ago