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Galina-37 [17]
3 years ago
11

Jose's school spent $1284 on 9 sticksof memory and a new hard drive. The hard drive cost $168. Which is the reasonable estimate

of the cost of one stick of memory?
Mathematics
2 answers:
myrzilka [38]3 years ago
4 0
Subtract the cost of the hard drive from the original $1284 and divide the answer you got by the 9 sticks of memory for your answer.
Andrews [41]3 years ago
4 0
Answer:$124 because you divide 1116 by 9
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A rectangular athletic field is three times as long as it is wide. If the perimeter of the athletic field is 128 yards, what are
larisa [96]
Length=3x
Width=x
3x+x+3x+x=128
8x=128
Divide both sides by 8
x=16
3(x)
3(16)=58
Width= 16 yards
Length= 58 yards
4 0
3 years ago
The workers in a senate office said that they received about 700 phone calls from
prohojiy [21]

Answer:

672

Step-by-step explanation:

anything lower then 5 or in this case 50 would round down so 649 rounds to 600 anything higher would round up 672 to 709 763 to 800 and 751 to 800

7 0
3 years ago
5.62 as a mixed number in simplest form
Andrej [43]
5.62 would be 5 62/100 then you can simplify the fraction down
62/100 - 31/50 
5 31/50
Hope I helped :)
6 0
3 years ago
Read 2 more answers
A 2003 study of dreaming found that out of a random sample of 106 ​people, 80 reported dreaming in color.​ However, the rate of
Vlad [161]

Answer:

Step-by-step explanation:

Hello!

You have the following experiment, a random sample of 106 people was made and they were asked if they dreamed in color. 80 persons of the sample reported dreaming in color.

The historical data from the 1940s informs that the population proportion of people that dreams in color is 0.21(usually when historical data is given unless said otherwise, is considered population information)

Your study variable is a discrete variable, you can define as:

X: Amount of people that reported dreaming in colors in a sample of 106.

Binomial criteria:

1. The number of observation of the trial is fixed (In this case n = 106)

2. Each observation in the trial is independent, this means that none of the trials will have an effect on the probability of the next trial (In this case, the fact that one person dreams in color doesn't affect or modify the probability of the next one dreaming in color)

3. The probability of success in the same from one trial to another (Or success is dreaming in color and the probability is 0.21)

So X~Bi(n;ρ)

In order to be able to run a proportion Z-test you have to apply the Central Limit Theorem to approximate the distribution of the sample proportion to normal:

^ρ ≈ N(ρ; (ρ(1-ρ))/n)

With this approximation, you can use the Z-test to run the hypothesis.

Now what the investigators want to know is if the proportion of people that dreams in color has change since the 1940s, so the hypothesis is:

H₀: ρ = 0.21

H₁: ρ ≠ 0.21

α: 0.10

The test is two-tailed,

Left critical value: Z_{\alpha/2} = Z_{0.95} = -1.64

Right critical value: Z_{1-\alpha /2} = Z_{0.95} = 1.64

If the calculated Z-value ≤ -1.64 or ≥ 1.64, the decision is to reject the null hypothesis.

If -1.64 < Z-value < 1.64, then you do not reject the null hypothesis.

The sample proportion is ^ρ= x/n = 80/106 = 0.75

Z= <u>     0.75 - 0.21    </u> = 12.83

    √[(0.75*0.25)/106]

⇒Decision: Reject the null hypothesis.

p-value < 0.00001 is less than 0.10

If you were to conduct a one-tailed upper test (H₀: ρ = 0.21 vs H₁: ρ > 0.21) with the information of this sample, at the same level 10%, the critical value would be Z_{0.90}1.28 against the 12.83 from the Z-value, the decision would be to reject the null hypothesis (meaning that the proportion of people that dreams in colors has increased.)

I hope this helps!

4 0
3 years ago
Solve -1/2w-3/5=1/5w
elena55 [62]
Very easy:

Common denominator:
-5/10w - 3/5 = 2/10w

- 3/5 = 7/10w

-30 = 35w

-30/35 = w

-6/7 = w


That's how you do it mate ;)
8 0
3 years ago
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