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2 years ago

Analyze the diagram below and complete the instructions that follow.

Mathematics

1 answer:

Jlenok [28]2 years ago

3 0

Step-by-step explanation:

$scale \: factor = \frac{7}{28} = \frac{1}{4} \\$

$ratio \:of \:surface \:areas\\=\frac{2[5\times 7 + 7\times 3+3\times 5]}{2[20\times 28+ 28\times 12+12\times 20] }\\\\=\frac{[35 + 21+15]}{[560+ 336+240] }\\\\=\frac{71}{1136}\\\\=\frac{1}{16}\\\\= 1\: :\: 16$

Read more about expressions at:

brainly.com/question/723406

8 0

1 year ago

Describe at least two differences between constructing parallel lines and

Marrrta [24]

Parallel lines never intersect purpendicular lines intersect at a single point forming a 90 degree angle

6 0

2 years ago

In Australia, road distance is measured in kilometres.

maks197457 [2]

Answer:

Step-by-step explanation:

5 miles-8km

x miles-120 km

x=120×5÷8

x=75 (miles)

3 0

2 years ago

Read 2 more answers

Tell whether the ratios are equivalent: 3 days to 4 hours and 9 days to 12 hours. Show your work.

antoniya [11.8K]

Answer

Step-by-step explanation:

Since you 4x3=12 3x3 = 9

3 0

2 years ago

Read 2 more answers

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago