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3 years ago

Find the distance between the points given. (2, 2) and (5, 5) 3 3√2 7√2

Mathematics

2 answers:

svetlana [45]3 years ago

8 0

Answer:

The answer is 3 square root 2.

Step-by-step explanation:

Using the distance formula and you will get 4.242...... and then you will get 3 square root 2.

Bond [772]3 years ago

3 0

Answer:distance=(3,3)

Step-by-step explanation:

5-2=3

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You are buying floor tile to cover a room that measures 13 feet by 22 feet. The tile is priced at $19.50 per square yard. How mu

egoroff_w [7]

1F=1/3Y

(1F)^2=(1/3Y)^2

F^2=1/9Y^2

------------------------

13F x 22F = 286F^2

-------------------------

286F^2 = 286 x 1/9 x Y^2

286F^2 = 286/9 Y^2

-------------------------

286/9 x $19.50 = $619.67

------------------------

Answer:

$619.67

3 0

3 years ago

Solve for x: 5/8=x-1/9 A. 37/8 B. 23/4 C. 11/2 D. 53/8

Vesna [10]

Answer:

53/72

Step-by-step explanation:

5/8 = x - 1/9

+1/9 +1/9

5/8 + 1/9 = x

9(5/8) + 8(1/9)

45/72 + 8/72

x= 53/72

8 0

2 years ago

At the beginning of a population study, a city had 360,000 people. Each year since, the population has grown by 4.3%.

dangina [55]

Answer: y = 360,000 times t + 4.3%

Step-by-step explanation:

6 0

2 years ago

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0

3 years ago

HELP PLEASE 14 POINTS

hram777 [196]

Answer:

To my knowledge of congruency, I would say the answer is A,

Step-by-step explanation:

Hope this helped!!!

8 0

2 years ago