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anzhelika [568]
3 years ago
6

A diner asks patrons for their preference for waffles or pancakes and syrup or fruit topping.

Mathematics
2 answers:
Anna35 [415]3 years ago
7 0

<u>Answer:</u>

Preference for waffies and syrup are dependent events and

P(waffies\mid syrup)\neq P(waffies)

<u>Step-by-step explanation:</u>

Since we have given that

P(waffies)=0.34

P(syrup\cap waffies)=0.32

As we know that if A and B are independent it must satisfy ,

PA\cap B)=P(A).P(B)

But here,

P(waffies\cap syrup)\neq P(waffies).P(syrup)\\0.32\neq 0.34\times 0.96\\0.32\neq 0.3264

Hence, they are not independent i.e. they are dependent.

And

P(waffies\mid syrup)\neq P(waffies)

Because,

P(waffies\mid syrup)\\\\=\frac{P(waffies\cap syrup)}{P(syrup)}\\\\=\frac{0.32}{0.96}\\\\=0.33

but,

P(waffies)=0.34


ivolga24 [154]3 years ago
5 0

Answer:

P (Waffles | Syrup)\neq P(Waffles)

Step-by-step explanation:

From the table we have to:

Probability of syrup is 0.96

Probability of waffles and syrup is 0.32

P (Waffles | Syrup) = P (Waffles and syrup) / P (syrup)

So:

If this equality is met, the probabilities are dependent, if on the contrary

P (Wafles | Syrup) = P (Wafles) then are independent probabilities.

P (Wafles | Syrup) = 0.32 / 0.96 = 0.333 \neq 0.32

So we have to:

P (Waffles | Syrup)\neq P(Waffles)

The probabilities are dependent.

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