19 divided by 27 is about 0.7, or 0.704 if you need a really exact answer.
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
4(2x + 10)=0
8x + 40 = 0
8x = -40
x = -5
Answer:
C. ![x>0](https://tex.z-dn.net/?f=x%3E0)
Step-by-step explanation:
Given: ![f(x)=log(8x)](https://tex.z-dn.net/?f=f%28x%29%3Dlog%288x%29)
To find the domain of a logarithmic function, we need to take the argument, 8x, and set it greater to zero. This is because an argument of a logarithmic function cannot be zero or negative.
![8x>0](https://tex.z-dn.net/?f=8x%3E0)
![x>0](https://tex.z-dn.net/?f=x%3E0)
So since x is greater than zero, we have just found out our domain:
Interval Notation: (0, ∞)
Set Notation: {
}