Answer:
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
Explanation:
Note: Refer the figure
Let the position of the lighthouse be 'L'
Given:
When the ship is at the position A, ∠DAL=37°
Now, when the ship sails through a distance of 2.5 i.e at position B
mathematically,
AB=2.5 miles
∠ABL=25°
Now,
∠DAL + ∠LAB = 180°
or
37° + ∠LAB = 180°
or
∠LAB = 180° - 37° = 143°
Also, In ΔLAB
∠LAB + ∠ABL + ∠ALB = 180°
or
143° + 25° + ∠ALB = 180°
or
∠ALB = 180° - 143° - 25° = 12°
Now using the concept of the sin law
In ΔLAB
or
AL = 5.08 miles
and,
or
BL = 7.23 miles
hence,
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
Answer:
field B = µ₀c I / 2πr
The field in the xy plane due to the fact that the two wires are perpendicular to the plane Bx and By are everywhere 0 on the plane.
a) Midway between, the Bz components cancel, so <0, 0, 0> T
b) Bz = µ₀ x I / 2πa + µ₀ x I / 2π(3a) = (µ₀ x I / 2π)(1/a + 1/3a)
Bz = (µ₀ x I / 2πr)(3/3a + 1/3a) = (µ₀x I / 2πr)(4 / 3a) = 2µ₀ x I / 3πa
c) By symmetry, Bz = -2µ₀ x I / 3πa (that is, down into the plane)
Answer:
It tells us
Explanation:
The number of valence shell electrons in an element's atom that is measured by a vertical column in the periodic table.
Answer:
D: 35 m/s
Explanation:
The bus is moving at a speed of 20 m/s.
Thus; v_bus = 20 m/s
Tennis ball thrown horizontally towards the front of the bus is given as 15 m/s.. Thus, v_ball = 15 m/s
No, due to the fact that the bus and the ball are moving at the same time, an observer will think the speed is the sum of that of the ball and the bus.
Thus, it will appear to an observer on the sidewalk that the speed is; v_bus + v_ball = 20 + 15 = 35 m/s
