Answer:
1 Newton
Explanation:
F=9*10^9*q0q1/r^2]]
F=9*10^9*(q0q1)/ r^2
r=3cm
F=4N
F=9*10^9*(q0q1)/3^2
4=9*10^9*(q0q1)/9
4=10^9 q0q1
q0q1=4/10^9
q0q1=4*10^-9
To calculate the force between the forces at a distance of 6 cm
F=9*10^9*(q0q1)/ r^2
=9*10^9*(4*10^-9)/6^2
=9*10^9*(4*10^-9)/36
=10^9*4*10^-9/4
=10^9*10^-9
=1 Newton
Depends, but generally, it does not include the day the order was placed.
Answer:
Centripetal force = 11789 N
Explanation:
Recall that the centripetal acceleration is defined as the square of the tangential velocity divided by the radius of the circular rotation. Then for our case, the centripetal acceleration is:
ac = (11.8 m/s)^2 / 15 m = 9.28266 m/s^2
then, such acceleration on a mass of 1270 kg will render a centripetal force of:
Fc = m * ac = 1270 * 9.28266 N = 11789 N
Answer:
See explanation
Explanation:
The centripetal force keeps an object moving in a circular orbit at constant velocity. The velocity of an object undergoing uniform motion is always tangential to the circle while the centripetal force is directed towards the center of the circle.
This now implies that the direction of the force acting on a body undergoing circular motion at constant velocity is perpendicular to the direction in which the object is being displaced.
Answer:
P = W / t = m g s / t = m g v where work by auto = m g s
30 kw = 30000 watts = 30000 J / s
Work wasted = F v as shown above relating work and power
Work done against incline = m g s sin 8.75 and power against incline
= m g v sin 8.75 = 1222 v Joules / sec
power in moving auto = power available - power lost to friction
power in moving auto = 30000 - resistance = 30000 - 910 v
1222 v = 30000 - 910 v
v = 30000 / 2132 = 14 m/s
Note: constant resistance to motion must mean P = W / t = F s / t = F v