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frosja888 [35]
3 years ago
14

A 60kg student is sitting in a chair and is not moving. what is the force of a student acting on the chair? what is the force of

the chair acting on the student?
Physics
1 answer:
vazorg [7]3 years ago
7 0

The force with which the student is acting in the chair and the force of the chair acting on the student is 588 N

Explanation:

  • There are two kinds of forces acting on you when you are sitting on the chair, they are the gravitational force and the force exerted by the chair on you.
  • The forces acting on the chair when you are sitting are the gravitational force and the force exerted by you.
  • As per  Newton's third law of motion, for every action, there is an equal and opposite reaction.
  • Hence, F = ma

        that is, F = 60 * 9.8

                       =588 N

  • So, 588 N force should be applied from both sides then only you can sit properly in the chair.
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Answer:

1 Newton

Explanation:

F=9*10^9*q0q1/r^2]]

F=9*10^9*(q0q1)/ r^2

r=3cm

F=4N

F=9*10^9*(q0q1)/3^2

4=9*10^9*(q0q1)/9

4=10^9 q0q1

q0q1=4/10^9

q0q1=4*10^-9

To calculate the force between the forces at a distance of 6 cm

F=9*10^9*(q0q1)/ r^2

=9*10^9*(4*10^-9)/6^2

=9*10^9*(4*10^-9)/36

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3 years ago
Does a business day include the day you ordered it?
Daniel [21]
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6 0
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A car of mass 1270 kg makes a 15.0 m radius turn at 11.8 m/s on flat ground. How much centripetal force acts on it?
svp [43]

Answer:

Centripetal force = 11789 N

Explanation:

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ac = (11.8 m/s)^2 / 15 m = 9.28266 m/s^2

then, such acceleration on a mass of 1270 kg will render a centripetal force of:

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3 years ago
what relationship must exist between an applied force and the velocity of a moving obkect if uniform circular motion is to resul
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Answer:

See explanation

Explanation:

The centripetal force keeps an object moving in a circular orbit at constant velocity. The velocity of an object undergoing uniform motion is always tangential to the circle while the centripetal force is directed towards the center of the circle.

This now implies that the direction of the force acting on a body undergoing circular motion at constant velocity is perpendicular to the direction in which the object is being displaced.

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Work done against incline = m g s sin 8.75  and power against incline

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Note: constant resistance to motion must mean P = W / t = F s / t = F v

7 0
3 years ago
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