<h3><u>Answer;</u></h3>
A.75°C
<h3><u>Explanation</u>;</h3>
Let the change in temp of cold water be x degrees,
while that of hot water be 100 - x degrees.
Heat exchange = mcΔt
Ice
Δt = x
m = 0.50 kg
c = 4.18 kJ/kg*°C
Hot water
Δt = 100 - x
m = 1.5 kg
c = 4.18
But;
Heat lost = heat gained
0.50 * c * x = 1.5 * c * (100 - x)
0.50 *x = 1.5*(100 - x)
0.5x = 150 - 1.5x
0.5x + 1.5x = 150 - 1.5x + 1.5x
2x = 150
x = <u>75° C</u>
Hence; the equilbrium temperature will be 75° C
Answer:
a) 166.4 s
b) (2.155 × 10⁷) s
Explanation:
15600 KWh for a year,
1 year consists of 365 × 24 hours = 8760 hours.
So, the power consumed in a year for an average household = (Energy/time)
= (15600/8760) = 1.781 KW = 1781 W
a) If the average rate of energy consumed by the house was instead diverted to lift a 1.80 × 10 3 kg car 16.8 m into the air, how long would it take
The power required for this lifting = (mgh/t)
m = 1800 kg
g = 9.8 m/s²
h = 16.8 m
t = ?
P = 1781 W
1781 = (1800×9.8×16.8)/t
t = (296,352/1781)
t = 166.4 s
b) how long would it take to lift a loaded Boeing 747 airplane, with a mass of 4.05 × 10 5 kg , to a cruising altitude of 9.67 km
The power required for this lifting = (mgh/t)
m = 405000 kg
g = 9.8 m/s²
h = 9.67 km = 9670 m
t = ?
P = 1781 W
1781 = (405000×9.8×9670)/t
t = (38,380,230,000/1781)
t = 21,549,820 s = (2.155 × 10⁷) s
Hope this Helps!!!
Answer:
The magnitude of the impulse delivered to the baseball is 7.0 Ns
Explanation:
Given;
mass of the foul ball, m = 0.14 kg
initial velocity, u = 40 m/s
final velocity, v = 30 m/s in perpendicular direction
Impulse is given as change in momentum;
initial momentum in horizontal direction, Pi = mu
Pi = 0.14 x 40 = 5.6 Ns
final momentum in perpendicular direction, Pf = mv
Pf = 0.14 x 30
Pf = 4.2 Ns
The resultant impulse is given by;
J² = 5.6² + 4.2²
J² = 49
J = √49
J = 7.0 Ns
Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns
60.9 - 4.9= 56
56 is the net force
using the formula F = ma
56= 8a
a = 7
acceleration is 7ms^-2