Answer:
Number of rocks and fossils collected by you is <u>1 and 24</u> respectively
Number of rocks and fossils collected by your friend is <u>3 and 12 </u>respectively
Step-by-step explanation:
Let the number of Rocks you collect be x
Let the number of Fossils you collect be y
Then the total number pf objects you collected will be
x + y = 25
x = 25 - y------------------------------(1)
Your friend collects three times as many rocks and half as many fossils as you.
This can be written as
3x + y (1/2) = 15
3x + (y/2) = 15-------------------(2)
Substituting (1) in (2)
3(25 - y) + (y/2) = 15
75 - 3y + (y/2) = 15
Grouping the like terms we get,
75 - 15 = 3y = (y/2)
60 = ( 6y - y /2)
60 x 2 = 6y -y
120 = 5y
y = 120/5
y = 24
Substituting y value in equation(1) we get
x = 25 - 24
x= 1
y= 24
Friends collects 3 times rock
so collects 3x =3(1) = 3rocks
Also he collects half as many fossils
That is
y/2 = 24/2 = 12 fossils
<u><em>Hope this help you! :)</em></u>
Answer:
Width = 9 yds
Length = 28 yds
Step-by-step explanation:
Width = x
Length = 2x + 10
Area is 252 yd²
x(2x + 10) = 252
2x² + 10x - 252 = 0
2 (x + 14) (x - 9) = 0
(x + 14) (x - 9) = 0
x = - 14 or x = 9
Width = 9 yds
Length = 2x9 + 10 = 28 yds
Answer:
0
Step-by-step explanation:
because
k c r
10 + (-10)
10 - 10=0
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
