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ivanzaharov [21]
3 years ago
10

Which of the following illustrates the truth value of the given conditional statement?

Mathematics
1 answer:
jeka57 [31]3 years ago
6 0
<span>I'm pretty sure it's F T → F. I can't believe nobody answered this question yet. SMH </span>
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All the events in the sample space that are not part of the specified event are called
natali 33 [55]

Answer:

All the events in the sample space that are not are the part of the specified event are All called the complement of the event.

Step-by-step explanation:

Suppose tossing a coin, the sample space here is {H,T}.

Now, if  the event is getting a head ,

so here T is not the part of the sample space and is called as complement of the event.

Therefore, all the events in the sample space that are not are the part of the specified event are All called the complement of the event.

7 0
3 years ago
What are the solutions of the equation (x-3)^2 + 2(x-3)-8=0
Lisa [10]
The solutions are x=5,-1<span />
8 0
3 years ago
What was the first step in Ghana’s independence? Kwame Nkrumah became the prime minister. A military coup seized power in the co
Anna35 [415]

Answer:

c

Step-by-step explanation:

The Africans gained a majority in the Parliament

8 0
3 years ago
Read 2 more answers
Expand the following: 1/3(6/5x-3)
Strike441 [17]
<span>x in (-oo:+oo)</span><span>

(1/3)*((6/5)*x-3) = 0</span><span>

1/3*(6/5*x-3) = 0</span><span>
( 1/3 )</span><span>

1/3 = 0</span><span>

x belongs to the empty set</span><span>

( 6/5*x-3 )</span><span>

6/5*x-3 = 0 // + 3</span><span>

6/5*x = 3 // : 6/5</span><span>

x = 3/6/5</span><span>

x = 5/2</span><span>

x = 5/2</span>
7 0
3 years ago
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Bad gums may mean a bad heart. Researchers discovered that 81% of people who have suffered a heart attack has periodontal diseas
IgorC [24]

Answer:

0.405 or 40.5%

Step-by-step explanation:

Let event A=having a periodontal disease

event B=having a heart attack

we are given

P(A)=P(having a periodontal disease)=0.30

P(B)=P(having a heart attack)=0.15

P(A/B)=P(have a periodontal disease/have a heart attack)=0.81

P(B/A)=P(have a heart attack/have a periodontal disease)=?

P(A/B)=P(A∩B)/P(B)

P(A∩B)=P(B)*P(A/B)=0.15*0.81=0.1215

P(B/A)=P(A∩B)/P(A)=0.1215/0.3=0.405

There is 40.5% probability that if someone has periodontal disease will have a heart attack.

7 0
3 years ago
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