All categories

3 years ago

I need help with these two questions!! I got 72° for Question 7, I don't know I need help with both of them!! PLEASE HELP!! :)

Mathematics

1 answer:

Nat2105 [25]3 years ago

3 0

Answer:

7. 49

8. 10.4

Step-by-step explanation:

7) our hypotenuse is 8, and the side opposite the base of ladder and ground angle is 6, therefore we can use Sin

sin = opposite/hypotenuse

sin(x) = 6/8 = 3/4

sin-1(3/4) = 49

8) using the theorem that alternate exterior angles are congruent

the angle opposite side x is 30

tan = opposite/adjacent

tan(30) = x/18

x = 18tan(30) = 6√(3) = 10.4

you can also use 30-60-90 special right triangles.

the side opposite 30 is x

side opposite 60 is x√(3)

and side opposite 90 is 2x

You might be interested in

Find the greatest common factor: 9a3bc2 + 12ac4 + 15a2b3c 3abc 15a3b3c4 3ac 9a2b2c2

VARVARA [1.3K]

The greatest common factor is 3abc

8 0

3 years ago

Find the length of the side of a square whose area is 2500 sq. cm PLS FIND ITS ANSWER............................

Sunny_sXe [5.5K]

Answer:

50cm

Step-by-step explanation:

The length of the square is the sway are root of its area.

square root of 2500 Is 50cm

Hope this helps.

Good Luck

4 0

3 years ago

Read 2 more answers

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago

Cole needs at least $815 to cover travel and hotel expenses for an upcoming national singing competition. He is setting up a wee

Ratling [72]

It would take 6 weeks for Cole to make 750$ and the 65$ he had received from the open mic would make it 815$

3 0

3 years ago

Read 2 more answers

In order to solve the equation −3x + 6 = 5, the first step is to

Angelina_Jolie [31]

The first step is to subtract 6 from both sides to cancel it out. You will be left with -3x= -1.

6 0

2 years ago

Read 2 more answers