r-12
substitute in r=7
so 7-12 = -5
2x - 3 < 11 or 8x -10 < 82: <span>X < 23/2
<span>
Part 1</span>
</span>2x-3<11
Add 3 both sides
2x-3+3<11+3
Refine
2x<14
Divide by 2 on both sides
2x / 2 / 14 / 2
Refine
x < 7
<span>
Part 2</span>
8x-10<82
Add 10 to both sides
8x-10+10<82+10
Refine
8x<92
Divide by 8
8x / 8 / 92 / 8
Refine
x < 23 / 2
Answer:
The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2
The rule of arithmetic sequence = a + d(n - 1)
Where a is the first term and n is the number of terms
So, for the even numbers between 0 and X
The first term = a = 0
d = 2
So, we need to find n at the last term which is X
∴ X = 0 + 2 ( n -1 )
∴ n - 1 = X/2
∴ n = X/2 + 1
The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)
Substitute with a and d and X
So, the sum = (n/2) * (2*0 + (n−1)*2)
= (n/2) * ((n−1)*2)
= n(n-1)
= (X/2 + 1) * (X/2)
= X/2 by (X/2 + 1)
So, The quick way to add all even numbers between 0 and X always works.
10
sum is add
cube is to the 3rd powr
19+x³
11.
product means multiply
3 times y is no more than (equal to or less than ) 21
3y≤21
no need to solve
12. 2 times difference is 10
difference is subtract
2(z-12)=10
Answer:
3. f(12) = -10; f(37) = -60
4. f(12) = -102; f(37) = -352
Step-by-step explanation:
3. Put the numbers in the formula and do the arithmetic:
f(12) = 12 -2(12-1) = 12 -22 = -10
f(37) = 12 -2(37-1) = 12 -72 = -60
__
4. The explicit formula for an arithmetic sequence with first term a1 and common difference d is ...
an = a1 +d(n -1)
Your sequence has a first term a1=8 and a common difference d=-10.
As above, fill in the numbers and do the arithmetic.
f(12) = 8 -10(12 -1) = -102
f(37) = 8 -10(37-1) = -352
