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yarga [219]
2 years ago
13

Plz help me I am so bad at math I will thank u and mark u branly

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
7 0
That is my home work also I will not tell you
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Can y’all give me the area of each figure
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Answer:

1. 208 in^2

Step-by-step explanation:

1. We can break the shape up into a rectangle in the middle and 2 triangles on either side of said rectangle.

The dimensions of the rectangle are 8 in by 20 in, and we only know one leg of the triangle as well as the hypotenuse.

If we know one leg and the hypotenuse we can use the pythagorean theormed to sovle for the other side and get 6 in.

So we have

(8 * 20) + 2((1/2)(6)(8))

160 + 48

208 in^2

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3 years ago
Which of the following sets of lengths can Sean use to make a right triangle?
Aleks [24]

Answer:

{8 cm, 15 cm, 17 cm}

Step-by-step explanation:

we know that

The length sides of a right triangle must satisfy the Pythagoras Theorem

so

c^2=a^2+b^2

where

c is the greater side (the hypotenuse)

a and b are the legs (perpendicular sides)

<u><em>Verify each case</em></u>

case 1) we have

{5 cm, 15 cm, 18 cm}

substitute in the formula

18^2=5^2+15^2

324=250 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 2) we have

{6 cm, 12 cm, 16 cm}

substitute in the formula

16^2=8^2+12^2

256=208 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 3) we have

{5 cm, 13 cm, 15 cm}

substitute in the formula

15^2=5^2+13^2

225=194 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 4) we have

{8 cm, 15 cm, 17 cm}

substitute in the formula

17^2=8^2+15^2

289=289 ----> is true

therefore

Sean can make a right triangle with this set of lengths

6 0
2 years ago
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