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denis23 [38]
3 years ago
13

I NEED HELP, I'VE BEEN STUCK ON THIS...Find the volume of this triangular prism. Enter only the numerical part of your answer in

square units.

Mathematics
2 answers:
777dan777 [17]3 years ago
7 0

Answer:

V = 240 m^3

Step-by-step explanation:

The volume of a triangular prism is

V = Bh  where B is the area of the base and h is the height

B = the area of the triangular base

B = 1/2 bh

B = 1/2 *5*12

B = 30 m^2

The volume is

V = 30 * 8

V = 240 m^3

deff fn [24]3 years ago
4 0

Answer:

[see below]

Step-by-step explanation:

Volume of a triangular prism is: V=\frac{1}{2}bhl

We are given the base of 5, the length of 12, and the height of 8. All measurements are in meters.

V=\frac{1}{2}(5*12*8)\\\\V=\frac{1}{2}(480)\\\\V=240

The volume of the prism should be 240 square meters.

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8 0
3 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
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