Question

The problem is in the picture ​

Answer 1

Answer:

x = 3 or 7

Step-by-step explanation:

Solve by completing the square:

$x^2 - 10x + 1 = -20$

First, move the constants to one side:

$x^2 - 10x = -21$

Then, add $(\frac{-10}{2})^2$ to both sides to make the right a perfect square trinomial, which is easy to factor:

$x^2 - 10x + (\frac{-10}{2})^2 = -21 + (\frac{-10}{2})^2$

Simplify and Factor:

$x^2 - 10x + 25 = -21 + 25$

$(x - 5)^2 = 4$

Finally, square root both sides using the even roots property:

$\sqrt{(x - 5)^2} = \sqrt{4}$

x - 5 = ± 2

x = 5 ± 2

x = 3   or   x = 7