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Margarita [4]
3 years ago
6

In 2002, the Bookstore sold 1000 paperback books and 1500 hardback books. In 2003, the store sold 15% more paperback books and 5

% more hardback books than sold in 2002. By what percent did the total number of books sold by the store increase from 2002 to 2003?. A. 20% / B. 60%. /C. 9% / D.15%
Mathematics
1 answer:
ratelena [41]3 years ago
7 0
Given:
2002 sold 1000 paperback books and 1500 hardback books for a total of 2,500 books.

2003 sold 15% more paperback books and 5% more hardback books.
1000 x 1.15 = 1,150 paperbacks
1500 x 1.05 = 1,575 hardbacks

1150 + 1575 = 2,725

2,725 - 2,500 = 225
225 / 2,500 = 0.09
0.09 x 100% = 9%  choice C

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Answer:

7.65 or 7.7 rounded to 1 DP

Step-by-step explanation:

To find the length of the side of a cube we do the inverse of finding the volume.

one side= x

If x³ = volume, therefore ∛448 is how to find the length of one side.

∛448= 7.65

I hope this helps you.

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3 years ago
(-4,-1), (4, 5)<br> What’s the slope
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Step-by-step explanation:

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If the sum of interior angle measures of a polygon is 720, how many sides does the polygon have?
NISA [10]
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3 years ago
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Assume a warehouse operates 24 hours a day. Truck arrivals follow Poisson distribution with a mean rate of 36 per day and servic
kirill [66]

The expected waiting time in system for typical truck is 2 hours.

Step-by-step explanation:

Data Given are as follows.

Truck arrival rate is given by,   α  = 36 / day

Truck operation departure rate is given,   β= 48 / day

A constructed queuing model is such that so that queue lengths and waiting time can be predicted.

In queuing theory, we have to achieve economic balance between number of customers arriving into system and that of leaving the system whether referring to people or things, in correlating such variables as how customers arrive, how service meets their requirements, average service time and extent of variations, and idle time.

This problem is solved by using concept of Single Channel Arrival with exponential service infinite populate model.

Waiting time in system is given by,

w_{s} = \frac{1}{\alpha - \beta  }

        where w_s is waiting time in system

                   \alpha is arrival rate described Poission distribution

                   \beta is service rate described by Exponential distribution

w_{s} = \frac{1}{\alpha - \beta  }

w_{s} = \frac{1}{48 - 36 }

w_{s} = \frac{1}{12 } day

w_{s} = \frac{1}{12 }  \times 24  hour        ...it is due to 1 day = 24 hours

w_{s} = 2 hours

Therefore, time required for waiting in system is 2 hours.

           

                   

5 0
3 years ago
X-2y=18 2x+y=6 parallel perpendicular or neither
sergey [27]
<h3>Therefore they are perpendicular.</h3>

Step-by-step explanation:

A equation of line is

y =mx +c

Here the slope of the line is m.

Given equations are

x - 2y = 18

⇔-2y = -x +18

\Leftrightarrow y =\frac{1}{2} x -9............(1)

and 2x + y = 6

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Therefore the slope of equation (1) is(m_1)= \frac{1}{2}

Therefore the slope of equation (2) is(m_2)= -2

If two lines are perpendicular, when we multiply their slope we get -1.

therefore,

m_1. m_2 =\frac{1}{2}. (-2) = -1

Therefore they are perpendicular.

4 0
3 years ago
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