You have cards with the letters A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P. Event U is choosing the cards A, B, C
Thepotemich [5.8K]
Answer:
If you are asking how many events use P: 1 event is using the letter P (event W)
Step-by-step explanation:
Why event U cannot be using P: This event is only using the letters A, B, C, and D.
Why event V cannot be using P: This event is only using vowels (A, E, I, O, U)
Answer:
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that a certain hockey team will win any given game is 0.3723
So
12 games in November
So
What is the probability that the hockey team wins 6 games in November?
This is
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Hi there!
The greatest common factor of 40 and 24 is 8.
8 goes into 40 5 times:
8 goes into 24 3 times.
We can rewrite this expression for distribution using the amount of times 8 goes into both numbers:
8(5 + 3)
Using this, we get:
8(5) + 8(3) = 40 + 24.
<em>To convert decimal number 1</em><em>2</em><em>3</em><em> to quinary, follow these steps:</em>
<em>1</em><em>.</em><em> </em><em>Divide 1</em><em>2</em><em>3</em><em> </em><em>by 5 keeping notice of the quotient and the remainder.</em>
<em>2</em><em>.</em><em>Continue dividing the quotient by 5 until you get a quotient of zero.</em>
<em>3</em><em>.</em><em> </em><em>Then just write out the remainders in the reverse order to get quinary equivalent of decimal number 1</em><em>2</em><em>3</em><em>.</em>
The answer is (0,-4),(1,0)