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frosja888 [35]
3 years ago
5

Helix Company has been approached by a new customer to provide 2,000 units of its regular product at a special price of $6 per u

nit. The regular selling price of the product is $8 per unit. Helix is operating at 75% of its capacity of 10,000 units. Identify whether the following costs are relevant to Helix's decision as to whether to accept the order at the special selling price. No additional fixed manufacturing overhead will be incurred because of this order. The only additional selling expense on this order will be a $0.50 per unit shipping cost. There will be no additional administrative expenses because of this order Calculate the operating income from the order Relevant Not Relevant Relevant Revenues Costs Revenue (cost) per unit a. Selling price b. Direct materials cost C. Direct labor cost d. Variable manufacturing overhead e. Fixed manufacturing overhead f. Regular selling expenses g. Additional selling expenses h. Administrative expenses 6.00 (2.00) (0.75) (0.50) (0.60) 2,000 Total operating income(loss) from special order Based on financial considerations alone, should Helix accept this order at the special price?

Business
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

1.)

Selling price - Relevant

Direct materials cost - Relevant

Direct labor cost - Relevant

Variable manufacturing overhead - Relevant

Fixed manufacturing overhead - Not relevant

Regular selling expenses - Not relevant

Additional selling expenses - Relevant

Administrative expenses - Not relevant

2.) Helix should accept the deal, with a net operating income of $2,000

Explanation:

Explanation to Question 2 can be found in the attached picture

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Answer:

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Using the continuous compounding equation, if someone invested $5,000 at an interest rate of 3.5%, and someone else invested $5,
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Therefore after 16.26 unit of time, both accounts have same balance.

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Explanation:

Formula for continuous compounding :

P(t)=P_0e^{rt}

P(t)=  value after t time

P_0= Initial principal

r= rate of interest annually

t=length of time.

Given that, someone invested $5,000 at an interest 3.5% and another one  invested $5,250 at an interest 3.2% .

Let after t year the both accounts have same balance.

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P(t)=5250e^{0.032t}

According to the problem,

5000e^{0.035t}=5250e^{0.032t}

\Rightarrow \frac{e^{0.035t}}{e^{0.032t}}=\frac{5250}{5000}

\Rightarrow e^{0.035t-0.032t}=\frac{21}{20}

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Taking ln both sides

\Rightarrow lne^{0.003t}=ln(\frac{21}{20})

\Rightarrow 0.003t}=ln(\frac{21}{20})

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\Rightarrow t= 16.26

Therefore after 16.26 unit of time, both accounts have same balance.

The account balance on that time is

P(16.26)=5000e^{0.035\times 16.26}

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The both account have $8,834.43.

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