Ask question

Ask question

All categories

tankabanditka [31]

3 years ago

7

Erin made 32 rings. She gives rings to 8 of her friends.Which two equations could be used to find the number of rings each frien

d gets?

1 answer:

kap26 [50]3 years ago

4 0

32 : 8 = x

32 x 1/8 = x

You might be interested in

John and 3 friends are going out for pizza for lunch. They split one pizza and 4 large drinks. The pizza cost $12.50. They spend

gladu [14]

The answer is $1.25 a large drink

Because 17.5 - 12.5 = 5 / 4 = $1.25

I hope this helps

8 0

3 years ago

The price of a shoes as reduced from 60 to 45. by what percentage was the price of the shoes reduced?

sweet-ann [11.9K]

45 is 75% of 60 but if you’re looking for the difference subtract 75 from 100, so 25%

8 0

2 years ago

What is the domain and range of the function?

Ierofanga [76]

Answer:

hello dude you see um this is complicated

Step-by-step explanation:

6 0

1 year ago

Solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the original logarithmic expressio

KIM [24]

Answer:

Therefore x=9

Step-by-step explanation:

Give that,

log x+ log (x-3) = log 54

log x(x-3) =log 54 [ $log_ca+log_c b=log_c(ab)$ ]

x(x-3) = 54

Now expand the above equation to get a quadratic equation

x²-3x=54

⇒x²-9x+6x-54=0

⇒x(x-9)+6(x-9)=0

⇒(x-9)(x+6)=0

⇒x-9=0 or, x+6=0

⇒x=9,-6

Now putting x= -6 in the given expression,

log(-6)+log(-6-9)=log 54.

Since log (-6) does not exist.

Therefore x=9

8 0

3 years ago

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago