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3 years ago

How is the genotype of the offspring different from that of the homozygous dominant parent?

Biology

1 answer:

tatuchka [14]3 years ago

8 0

Since it's been crossed with a homozygous wrinkled green, the offspring has a genotype for heterozygous round and yellow. As round and yellow are dominant traits, they're expressed in the phenotype. But when self pollinated in the f2 generation, the recessive ones will show as well

Hope it helps :')

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In plants tall (T) is dominant to short (t) and round seed is dominant to wrinkled seeds (r). If a parent is short and wrinkled

Nuetrik [128]

Answer:

Parent cross= ttrr (short, wrinkled) × TtRr (hybrid)

POSSIBLE GAMETES BY EACH PARENT:

ttrr - tr, tr, tr, and tr

TtRr - TR, Tr, tR, and tr

Explanation:

This question involves two genes in a certain plant. One gene is coding for height while the other is coding for seed shape. The alleles for tallness (T) and round seeds (R) is dominant over the alleles for shortness (t) and wrinkled seeds (r).

According to this question, a parent that is short and wrinkled (ttrr) is crossed with another parent that is hybrid (TtRr) for both traits. This means that the parent cross is as follows: ttrr × TtRr

The possible combination of gametes that will be produced by each parent is as follows:

ttrr - tr, tr, tr, and tr

TtRr - TR, Tr, tR, and tr

See attached image for the punnet square using these gametes.

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Learn more about anticodons at: brainly.com/question/26494180

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