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Mrac [35]
3 years ago
10

An electric field of 260000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -

6.7C at this spot?
Physics
1 answer:
olga55 [171]3 years ago
3 0

Answer:

Electric force on the charge will be equal to -1742000 N

Explanation:

We have given electric field at a point is E = 260000 N/C

And charge q = -6.7 C

We have to find the force on that charge

Force on the charge is equal to Force = charge × electric field ( multiplication of electric field and charge )

So force will be equal to F=260000\times -6.7=-1742000N

So electric force on the charge will be equal to -1742000 N

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Answer:

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Explanation:

Hello!

The free fall of the stone corresponds to a uniformly varied rectilinear movement

d=V_0*t+1/2*g*t^2

Being a free fall the initial speed is zero.

The distance is positive when considered in the same direction and direction as acceleration and speed.

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121.92m=0 m⁄s*t+1/2*9,8 m⁄s^2 *t^2

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success with your homework!

Download pdf
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