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3 years ago

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An electric field of 260000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -

6.7C at this spot?

1 answer:

olga55 [171]3 years ago

3 0

Answer:

Electric force on the charge will be equal to -1742000 N

Explanation:

We have given electric field at a point is E = 260000 N/C

And charge q = -6.7 C

We have to find the force on that charge

Force on the charge is equal to Force = charge × electric field ( multiplication of electric field and charge )

So force will be equal to $F=260000\times -6.7=-1742000N$

So electric force on the charge will be equal to -1742000 N

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An 8 g bullet leaves the muzzle of a rifle with

Elena-2011 [213]

Answer: 1872 N

Explanation:

This problem can be solved by using one of the Kinematics equations and Newton's second law of motion:

$V^{2}=V_{o}^{2} + 2ad$ (1)

$F=ma$ (2)

Where:

$V=611.9 m/s$ is the bullet's final speed (when it leaves the muzzle)

$V_{o}=0$ is the bullet's initial speed (at rest)

$a$ is the bullet's acceleration

$d=0.8 m$ is the distance traveled by the bullet before leaving the muzzle

$F$ is the force

$m=8 g \frac{1 kg}{1000 g}=0.008 kg$ is the mass of the bullet

Knowing this, let's begin by isolating $a$ from (1):

$a=\frac{V^{2}}{2d}$ (3)

$a=\frac{(611.9 m/s)^{2}}{2(0.8 m)}$ (4)

$a=234013.5063 m/s^{2} \approx 2.34(10)^{5} m/s^{2}$ (5)

Substituting (5) in (2):

$F=(0.008 kg)(2.34(10)^{5} m/s^{2})$ (6)

Finally:

$F=1872 N$

4 0

3 years ago

Work is done when : 11 point)

LuckyWell [14K]

I think it’s the first one

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3 years ago

BRAINLIEST WILL BE MARKED FOR THE FIRST ANSWER

slamgirl [31]

Answer:

The weight of the body in the new planet is 100 newtons.

Explanation:

From Newton's Law of Gravitation we find that gravitational force is directly proportional to mass of the planet and inversely proportional to the square of its radius. From this fact we can build the following relationship:

$\frac{F_{1}\cdot R_{1}^{2}}{M_{1}} = \frac{F_{2}\cdot R_{2}^{2}}{M_{2}}$ (1)

Where:

$F_{1}$ , $F_{2}$ - Gravitational force, measured in newtons.

$M_{1}$ , $M_{2}$ - Mass of planet, measured in kilograms.

$R_{1}$ , $R_{2}$ - Radius of the planet, measured in meters.

If we know that $F_{1} = 800\,N$ , $\frac{M_{2}}{M_{1}} = \frac{1}{2}$ and $\frac{R_{2}}{R_{1}} = 2$ , then the expected gravitational force in the new planet is:

$F_{2} = F_{1}\cdot \left(\frac{M_{2}}{M_{1}} \right)\cdot \left(\frac{R_{1}} {R_{2}}\right)^{2}$

$F_{2} = (800\,N)\cdot \left(\frac{1}{2} \right)\cdot \left(\frac{1}{2}\right)^{2}$

$F_{2} = 100\,N$

The weight of the body in the new planet is 100 newtons.

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A student notices that a reaction takes place faster when the temperature is higher. Which best explains why this happens?

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