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Talja [164]
4 years ago
5

What is the anode in an alkaline battery?

Physics
2 answers:
Shalnov [3]4 years ago
5 0

Answer:

the anode in an alkaline battery is typically made from zinc

Explanation:

andrew-mc [135]4 years ago
3 0

For instance, in an alkaline battery, the anode is typically made of zinc, and manganese dioxide acts as the cathode. And the electrolyte between and inside those electrodes contains ions. ... These free electrons congregate inside the anode (the bottom, flat part of an alkaline battery)

Hope this helps:)

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Prove that f=ma where the symbols have their usual meaning.​
jekas [21]

Explanation:

According to Newton's second law of motion:

Force is directly proportional to

Change of momentum/time taken

Change of momentum= mv-mu

where m is mass, u is initial velocity and v is final velocity. so,

F∝mv-mu/t

F∝m(v-u)/t

F∝ma (a=v-u/t)

F=kma where k is a constant

In SI units the value of k will become one so the equation will be:

F=ma

7 0
3 years ago
A 1.4-kg cart is attached to a horizontal spring for which the spring constant is 50 N/m . The system is set in motion when the
marin [14]

Answer:

A)

0.395 m

B)

2.4 m/s

Explanation:

A)

m = mass of the cart = 1.4 kg

k = spring constant of the spring = 50 Nm⁻¹

x = initial position of spring from equilibrium position = 0.21 m

v_{i} = initial speed of the cart = 2.0 ms⁻¹

A = amplitude of the oscillation = ?

Using conservation of energy

Final spring energy = initial kinetic energy + initial spring energy

(0.5) kA^{2} = (0.5) m v_{i}^{2} + (0.5) k x_{i}^{2} \\kA^{2} = m v_{i}^{2} + k x_{i}^{2} \\(50) A^{2} = (1.4) (2.0)^{2} + (50) (0.21)^{2} \\A = 0.395 m

B)

m = mass of the cart = 1.4 kg

k = spring constant of the spring = 50 Nm⁻¹

A = amplitude of the oscillation = 0.395 m

v_{o} = maximum speed at the equilibrium position

Using conservation of energy

Kinetic energy at equilibrium position = maximum spring potential energy at extreme stretch of the spring

(0.5) m v_{o}^{2} = (0.5) kA^{2}\\m v_{o}^{2} = kA^{2}\\(1.4) v_{o}^{2} = (50) (0.395)^{2}\\v_{o} = 2.4 ms^{-1}

5 0
4 years ago
Read 2 more answers
A drowsy cat spots a flowerpot that sails first up and then down past an open window. The pot is in view for a total of 0.50 s,
borishaifa [10]

Answer:

2.34 m

Explanation:

The cat saw the pot for 0.25 s each time. use the second equation of motion to find the velocity of the pot.

x= ut + 0.5 at²

x = 2.00 m

t = 0.25 s

a = - g = -9.8 m/s²

2.00 -0 = u (0.25) - 0.5 (9.8) (0.25)²

⇒u = 9.225 m/s

Use the third equation of motion:

2as = v²-u²

at highest point, final velocity is zero. v = 0.  a =-g = -9.8 m/s²

s = -(9.225)²/(-9.8×2) =4.34 m

The height above the window top:

4.34 m - 2 m = 2.34 m

8 0
3 years ago
In a single-slit diffraction experiment, the width of the slit through which light passes is reduced. What happens to the width
ArbitrLikvidat [17]

Answer:

It becomes wider

Explanation:

Because The bigger the object the wave interacts with, the more spread there is in the interference pattern. Decreasing the size of the opening increases the spread in the pattern.

6 0
3 years ago
Add a picture of leaves.
iren2701 [21]

Answer:

There you go

Explanation:

 

6 0
4 years ago
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