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Aneli [31]
3 years ago
13

Two forces have magnitudes in the ratio

Physics
1 answer:
rewona [7]3 years ago
8 0

Answer:

F1=26N and F2=09N ..this is from the two simultaneously equations

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How much energy must be added to a 2-kg piece of glass with a specific heat
MAXImum [283]

Answer:

51520J

Explanation:

The energy added to the piece of glass is also called heat needed to increase its temperature from 10°C to 50°C and it depends on the mass, specific heat capacity and the change in temperature.

Q=m.c.ΔT

Q=(2kg).(644J/(kg°C)).((50°C)-(10°C))

Q=51520J                    

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3 years ago
Competitive divers pull their limbs in and curl up their bodies when they do somersaults. Just before entering the water, they f
Akimi4 [234]

Answer:

The angular velocity is reduced when the body is fully stretched.

Explanation:

Divers keep there bodies as compact as possible just to increase the angular velocity.

When they extend their limbs to enter straight down the angular momentum helps them to dive. The angular velocity is reduced when the body is fully stretched and diver's inertia is also not reduced. Thus a streamlined shape is formed which helps to penetrate more deeper into the water.

The impact area is reduced when fully stretched body is entered in to the water.

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3 years ago
Which of the following is not a function of protein?
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Answer: I Believe The Answer Is A. Insulating The Body

5 0
3 years ago
Read 2 more answers
A point charge with charge q1 = 4.00 μC is held stationary at the origin. A second point charge with charge q2 = -4.40 μC moves
Bezzdna [24]

Answer:

W=0.94J

Explanation:

Electrostatic potential energy is the energy that results from the position of a charge in an electric field. Therefore, the work done to move a charge from point 1 to point 2 will be the change in electrostatic potential energy between point 1 and point 2.

This energy is given by:

U=\frac{K\left |q_1 \right |\left |q_2 \right |}{r}\\

So, the work done to move the chargue is:

W=U_1-U_2\\W=\frac{K\left |q_1 \right |\left |q_2 \right |}{r_1}-\frac{K\left |q_1 \right |\left |q_2 \right |}{r_2}\\r_1=\sqrt{((0.155 m)^2+0 m)^2}=0.115m\\r_2=\sqrt{((0.245 m)^2+(0.270 m)^2}=0.365m\\W=K\left |q_1 \right |\left |q_2 \right |(\frac{1}{r_1}-\frac{1}{r_2})\\W=8.99*10^9\frac{Nm^2}{c^2}(4.00*10^{-6}C)(4.40*10^{-6}C)(\frac{1}{0.115m}-\frac{1}{0.365})\\W=0.94J

The work is positive since the potential energy in 1 is greater than 2.

5 0
4 years ago
Consider a single slit diffraction pattern for awavelength of 589 nm porjected ona screen that is 100m from a slit of width 0.25
3241004551 [841]

Answer:

c

Explanation:

6 0
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