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GrogVix [38]
3 years ago
5

7. REINFORCE The faces of a six-sided number cube are labeled with even numbers: 2, 4, 6,

Mathematics
1 answer:
julsineya [31]3 years ago
3 0

Answer:

P(2)= 1/6

P(4)=1/6

P(6)=1/6

P(8)=1/6

P(10)=1/6

P(12)=1/6

Step-by-step explanation:

The number of possible outcomes us still 6 as the dice is said to be six sided.

Probability= no of desired outcome/no of possible outcome

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If line segment AB measures approximately 8.6 units and is considered the base of parallelogram ABCD, what is the approximate co
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Answer:

4.8

Step-by-step explanation:

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The owner of the Koffee Shop pours the remainder of her old house blend, which is 40 % 40 % Colombian beans, into a 60 60 -pound
maks197457 [2]

Answer:

0.4h ; 60 - h ;18 - 0.3h ; 0.1h + 18

Step-by-step explanation:

Given that:

Old house blend = 40% Columbian beans

New house blend = 30% Columbian beans

h = number of pounds of old house blend

a.) pound of columbian bean in old house blend :

40% of h = 0.4h

b.) pound of new blend poured into the bean:

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Size of bin - pound of old house blend

(60 - h)

c. Amount of columbian bean in pound of new house blend :

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0.3 * (60 - h)

18 - 0.3h

D.) Amount of columbian bean in 60 pound bin

(Pound of columbian bean in old house blend + pound of Columbian bean in New house blend)

0.4h + (18 - 0.3h)

0.4h + 18 - 0.3h

0.1h + 18

4 0
3 years ago
Triangle ABC has coordinates A(1, 1); B(2, 5); C(5, 1). What would be the coordinates of A'B'C' if you translated ABC left 2 and
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Answer:

A'(-1, 6) B'(0, 10) C'(3, 6)

8 0
3 years ago
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How do you solve <br> 10 squared + 13 squared = c squared<br> (Pythagorean theorem)
alina1380 [7]
10^2 + 13^2 =c^2\\\\100 + 169=c^2\\\\269 = c^2\\\\\boxed{\bf{c=\sqrt{269}\approx 16.4}}
5 0
3 years ago
Is this the correct answer?
Step2247 [10]

Step-by-step explanation:

Close.  You correctly set up the integrals.  When integrating e²ˣ:

∫ e²ˣ dx

½ ∫ 2 e²ˣ dx

½ e²ˣ + C

So the coefficient should be ½, not 2.

[eˣ − ½ e²ˣ]₋₁⁰ + [½ e²ˣ − eˣ]₀¹

[(e⁰ − ½ e⁰) − (e⁻¹ − ½ e⁻²)] + [(½ e² − e) − (½ e⁰ − e⁰)]

1 − ½ − e⁻¹ + ½ e⁻² + ½ e² − e − ½ + 1

-e⁻¹ + ½ e⁻² + ½ e² − e  + 1

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