Answer:
0.4h ; 60 - h ;18 - 0.3h ; 0.1h + 18
Step-by-step explanation:
Given that:
Old house blend = 40% Columbian beans
New house blend = 30% Columbian beans
h = number of pounds of old house blend
a.) pound of columbian bean in old house blend :
40% of h = 0.4h
b.) pound of new blend poured into the bean:
Size of bin = 60 pound
Size of bin - pound of old house blend
(60 - h)
c. Amount of columbian bean in pound of new house blend :
30% of (60 - h)
0.3 * (60 - h)
18 - 0.3h
D.) Amount of columbian bean in 60 pound bin
(Pound of columbian bean in old house blend + pound of Columbian bean in New house blend)
0.4h + (18 - 0.3h)
0.4h + 18 - 0.3h
0.1h + 18
Step-by-step explanation:
Close. You correctly set up the integrals. When integrating e²ˣ:
∫ e²ˣ dx
½ ∫ 2 e²ˣ dx
½ e²ˣ + C
So the coefficient should be ½, not 2.
[eˣ − ½ e²ˣ]₋₁⁰ + [½ e²ˣ − eˣ]₀¹
[(e⁰ − ½ e⁰) − (e⁻¹ − ½ e⁻²)] + [(½ e² − e) − (½ e⁰ − e⁰)]
1 − ½ − e⁻¹ + ½ e⁻² + ½ e² − e − ½ + 1
-e⁻¹ + ½ e⁻² + ½ e² − e + 1
