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4vir4ik [10]
3 years ago
9

ASAP pls helppppppppppppppppp!!!

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

The answer is 7.

Look at the x=8 and then look up the y-value.

The graph passes (8,7) so therefore when x = 8 the y is 7

You might be interested in
What shape best describes the cross section cut at an angle to the base of a right rectangular prism? Trapezoid Parallelogram Sq
andreev551 [17]

Answer:

Rectangle.

Step-by-step explanation:

The 2 dimensional section would be a rectangle.

5 0
3 years ago
Can someone please help me with these two please I'll appreciate it :)
s344n2d4d5 [400]
4.

\sqrt{64}=8\\\\8\dfrac17=8.14285714...\\\\8.\overline{14}=8.14141414...\\\\ \dfrac{15}2=7,5\\\\\\ \boxed{\ \dfrac{15}2\ \ \textless \ \ \sqrt{64}\ \ \textless \ \ 8.\overline{14}\ \ \textless \ \ 8\dfrac17\ }

5.

\sqrt{18}  doesn't belong with the other three because it is irrational number
The other three can be expressed as a ratio between two <span>integers.

-\dfrac{10}2=\dfrac{-10\ }2\\\\-13.4=-13\frac4{10}=\frac{-134}{\ 10}\\\\ 22.\overline7=22\frac79=\frac{205}9\\\\\\ \sqrt{18}=\sqrt{9\cdot2}=\sqrt9\cdot\sqrt2=3\sqrt2
</span>

7 0
3 years ago
Mark wants to fence 4 rectangular gardens, each with a length of 9 1/4 feet and a width of 4 1/2feet. What is the length of fenc
kolbaska11 [484]

Answer:

110 ft  

Step-by-step explanation:

The length of fencing is four times the perimeter of one garden.

The formula for the perimeter of a rectangle is  

P = 2l + 2w

The total perimeter for all four rectangles is

P = 4× (2l + 2w) = 8l + 8w

Data:

 l = 9¼ ft

w = 4½ ft

Calculation:

P = 8l + 8w = 8×9¼ + 8×4½ = 72⁸/₄ + 32⁸/₂ =(72 + 2) + (32 + 4) = 74 + 36 = 110 ft

The total length of fencing is 110 ft.

4 0
3 years ago
PRE ALGEBRA / PLEASE HELP!!||| How many kilometers is it from the main gate to the Manatee Springs? (Hint: to convert from yards
mars1129 [50]

Answer:

  • 6.04 km (per angle marks)
  • 5.36 km (per side hash marks)

Step-by-step explanation:

Going by the angle indicators, the ratios of corresponding sides of the similar triangles are ...

  x/2000 = 4200/3500

  x = 2000·6/5 = 2400 . . . . yards

Then the distance of interest is ...

  (2400 yd + 4200 yd)×(0.0009144 km/yd) = 6.6×.9144 km

  = 6.03504 km ≈ 6.04 km

_____

Going by the red hash marks, the ratios of corresponding sides of the similar triangles are ...

  x/2000 = 3500/4200

  x = 2000·(5/6) = 5000/3 . . . . yards

Then the distance of interest is ...

  (5000/3 + 4200) yd × 0.0009144 km/yd ≈ 5.36 km

_____

<em>Comment on the figure</em>

The usual geometry here is that the outside legs (opposite the vertical angles) are parallel, meaning that the angle indicators are the correct marks. It is possible, but unusual, for the red hash marks to be correct and the angle indicators to be mismarked. The red hash marks seem tentatively drawn, so seem like they're more likely to be the incorrect marks.

7 0
3 years ago
Read 2 more answers
10# A consumer advocacy group is doing a large study on car rental practices. Among other things, the consumer group would like
ella [17]

ANSWER:

104

STEP-BY-STEP EXPLANATION:

Given:

Standard deviation (σ) = 700

Confidence level = 95%

Mean error (Eμ) = 135

We have for a confidence level of 95%:

\begin{gathered} \alpha=100\%-95\%=5\%=0.05 \\  \\ \alpha\text{/2}=\frac{0.05}{2}=0.025 \\  \\ \text{ The corresponding Z value for \alpha/2 = 0.025 is as follows:} \\  \\ Z_{\alpha\text{/2}}=1.96 \end{gathered}

Now, we calculate the minimum value of the sample size as follows:

\begin{gathered} n=\left(\frac{Z_{\alpha\text{/2}}\cdot\sigma}{E}\right)^2 \\  \\ \text{ We replacing:} \\  \\ \:n=\left(\frac{1.96\cdot 700}{135}\right)^2 \\  \\ \:n=103.2858\cong104 \end{gathered}

The minimum sample size needed is 104

3 0
1 year ago
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