Answer:
The objective function in terms of one number, x is
S(x) = 4x + (12/x)
The values of x and y that minimum the sum are √3 and 4√3 respectively.
Step-by-step explanation:
Two positive numbers, x and y
x × y = 12
xy = 12
S(x,y) = 4x + y
We plan to minimize the sum subject to the constraint (xy = 12)
We can make y the subject of formula in the constraint equation
y = (12/x)
Substituting into the objective function,
S(x,y) = 4x + y
S(x) = 4x + (12/x)
We can then find the minimum.
At minimum point, (dS/dx) = 0 and (d²S/dx²) > 0
(dS/dx) = 4 - (12/x²) = 0
4 - (12/x²) = 0
(12/x²) = 4
4x² = 12
x = √3
y = 12/√3 = 4√3
To just check if this point is truly a minimum
(d²S/dx²) = (24/x³) = (8/√3) > 0 (minimum point)
Answer:
Difference of squares:
y^4−25
16x^2−81
Not difference of squares:
20m^2n^2−121
p^8−q^5
Step-by-step explanation:
y^4−25
(y²)² - 5²
16x^2−81
(4x)² - 9²
20m^2n^2−121
20 is not a perfect square
p^8−q^5
q⁵ is not a perfect square
Answer:
(1, 3)
Step-by-step explanation:
Given coordinates of 2 endpoints, G(-2, 5) and H(4, 1), midpoint of AB is calculated as shown below:
Midpoint (M) of GH, for G(-2, 5) and H(4, 1) is given as:

Let 

Thus:



Coordinates of the midpoint of GH = (1, 3).
Answer:
12
trust me it works i just took the test.
Answer:
Step-by-step explanation:
your answer is the 2 option