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vitfil [10]
3 years ago
14

3. Do some Internet research on the use of VLANs in hospitals. Summarize the benefits of using VLANs in hospitals and identify e

xamples of how St. Luke’s could further enhance its wireless network by implementing VLANs.
Computers and Technology
2 answers:
motikmotik3 years ago
5 0

VLAN refers to Virtual Local Area Network. It is a subnetwork that can group together collection of devices on separate physical Local Area Networks. VLANs allow network administrators to group hosts together even if the hosts are not directly connected to the same network switch.

Considering the large number of departments in hospitals, with each departments having functions different from the others, Virtual LANs allows various users(the departments) to be grouped together according to their networking needs, regardless of their actual physical locations. Subdividing the LAN into smaller segments, or VLANs, increases overall reliability, security, and performance, and makes the network easier to maintain.

Because of the largeness of St. Luke's hospitals and their mission of delivering highly reliable and feature-rich advanced network solutions, virtual LAN will help to provide a resilient and scalable network solution within the hospital's budget.

St. Luke should implement virtual LAN that can produce a higher bandwidth with lower-cost, a longer-term model based on servers, networking products and homogenous network components to deliver centralized management of computing across the hospital network.

zimovet [89]3 years ago
4 0

Answer:

VLAN NETWORK3The Use and Benefits of VLANs in Hospitals, With Examples How St. Luke’s Hospital Could Further Improve Its Wireless Net by Implementing VLANs

Explanation:

The Use and Benefits of VLANs in Hospitals, With Examples How St. Luke’s Hospital Could Further Improve Its Wireless Net by Implementing VLANs.Virtual LAN (VLAN) allows a network administrator to manage multiple networks even if there are not on a similar framework switch. The merits of utilizing Virtual LANs in human services office incorporate; cost reduction in that a particular switch can be utilized and isolate different divisions framework traffic. VLANs logically separate network traffic deterring devicesfrom interfering to any net traffic on other VLANs, this enhances safety. They offer extra assurance by VLANs gadget commitment. VLANs improves better execution by dropping broadcast traffic. They empower simple manageable switch structure, for example, VLAN trunk convention, convey easy delivery VLANs through a physical net environment. VLANS empowersimple availability, where the nature of program movement experienced today is altogether less than it was before.In the case of St. Luke’s health care facility (), it could supplementary advance its wireless structure by initiating VLANs, for example: the Information Technology administration at the facility observe wireless networking as the main player in their major objectives to increase clinician effectiveness and advanced patient consideration. Moveable EKG components have been connected dropping the total number of wireless gadgets in use significantly. Also Mobility XE facilitates St. Luke’s Information Technology division to fundamentally succeed all the wireless devices operated by clinicians. Lastly, the gadgets that arenot recognized by the Mobility XE server are not allowed to commerce the network improving the hospital data protection.

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Using the knowledge in computational language in C++ it is possible to write a code that  cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]  </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em>    if (digit == limit) {</em>

<em>        ans += (sum == 0);</em>

<em>        return sum == 0;</em>

<em>    }</em>

<em>    // if summation at digit position complete, validate it with result[digit].</em>

<em>    if (widx == words.size()) {</em>

<em>        if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em>            if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em>                return false;</em>

<em>            c2i[result[digit]] = sum % 10;</em>

<em>            i2c[sum%10] = result[digit];</em>

<em>            bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em>            c2i.erase(result[digit]);</em>

<em>            i2c.erase(sum%10);</em>

<em>            ans += tmp;</em>

<em>            return tmp;</em>

<em>        } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em>            if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em>                return false;</em>

<em>            }</em>

<em>            return helper(words, result, digit+1, 0, sum/10);</em>

<em>        } else {</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

<em>    // if word[widx] length less than digit, ignore and go to next word</em>

<em>    if (digit >= words[widx].length()) {</em>

<em>        return helper(words, result, digit, widx+1, sum);</em>

<em>    }</em>

<em>    // if word[widx][digit] already mapped to a value</em>

<em>    if (c2i.count(words[widx][digit])) {</em>

<em>        if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em>            return false;</em>

<em>        return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em>    }</em>

<em>    // if word[widx][digit] not mapped to a value yet</em>

<em>    for (int i = 0; i < 10; i++) {</em>

<em>        if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em>        if (i2c.count(i)) continue;</em>

<em>        c2i[words[widx][digit]] = i;</em>

<em>        i2c[i] = words[widx][digit];</em>

<em>        bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em>        c2i.erase(words[widx][digit]);</em>

<em>        i2c.erase(i);</em>

<em>    }</em>

<em>    return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em>    limit = result.length();</em>

<em>    for (auto &w: words) </em>

<em>        if (w.length() > limit) </em>

<em>            return;</em>

<em>    for (auto&w:words) </em>

<em>        reverse(w.begin(), w.end());</em>

<em>    reverse(result.begin(), result.end());</em>

<em>    int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em>    ans = 0;</em>

<em>    vector<string> words={"GREEN" , "BLUE"} ;</em>

<em>    string result = "BLACK";</em>

<em>    isSolvable(words, result);</em>

<em>    cout << ans << "\n";</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

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