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Angelina_Jolie [31]
3 years ago
7

How do you solve 3(2×+5)-(4×_9)

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer: 3(2×+5)-(4×9) = -15

Step-by-step explanation:

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A box is partially filled with books. If 24 cubic inches of the box are already filled and there are 12 cubic inches of space le
nikitadnepr [17]

Answer:

The box has a total volume of 36 cubic inches.

Step-by-step explanation:

The total volume of the box is given by the volume that is filled with books plus the volume that doesn't have any books in it. Therefore, in order to solve this problem we must sum the two volumes. We have:

total volume = volume with books + volume without books

total volume = 24 + 12

total volume = 36 cubic inches

The box has a total volume of 36 cubic inches.

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3 years ago
Which equation could be used to solve problems involving the relationships between the angles?
babymother [125]
I would either go with a or c
6 0
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Sandra bought 5 pounds of sweet potatoes for $7.25. What is the cost per pound of the sweet potatoes?
diamong [38]

the cost per pound is 1.45 .

8 0
3 years ago
Read 2 more answers
Convert angle 0=70 to radians
GREYUIT [131]

Answer:

1.57 radians

Step-by-step explanation:

Divide both sides by 360, you get 1° = π/180. This means 70° is equal to (70)(π/180). Then simplify this, and 70° = (7π)/18 radians, or approximately 1.221730476396 radians. This seems reasonable because 90°, is a quarter circle and (1/4) of 2π is π/2, which is approximately 1.57 radians.

3 0
3 years ago
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How do you do this question?
irga5000 [103]

Answer:

π/6 [37^(³/₂) − 1] ≈ 117.3187

Step-by-step explanation:

The surface area is:

S = ∫ 2π (x − 0) √(1 + (dx/dy)²) dy

0 ≤ x ≤ 3, so -4 ≤ y ≤ 5.

Find dx/dy.

y = 5 − x²

x² = 5 − y

x = √(5 − y)

dx/dy = ½ (5 − y)^(-½) (-1)

dx/dy = -½ (5 − y)^(-½)

(dx/dy)² = ¼ (5 − y)^(-1)

(dx/dy)² = 1 / (4 (5 − y))

Plug in:

S = ∫₋₄⁵ 2π x √(1 + 1 / (20 − 4y)) dy

S = ∫₋₄⁵ 2π √(5 − y) √(1 + 1 / (4 (5 − y))) dy

S = ∫₋₄⁵ 2π √((5 − y) + 1/4)) dy

S = ∫₋₄⁵ 2π √(5.25 − y) dy

If u = 5.25 − y, then du = -dy.

S = ∫ 2π √u (-du)

S = -2π ∫ √u du

S = -2π (⅔ u^(³/₂))

S = -4π/3 u^(³/₂)

Substitute back:

S = -4π/3 (5.25 − y)^(³/₂)

Evaluate between y=-4 and y=5.

S = [-4π/3 (5.25 − 5)^(³/₂)] − [-4π/3 (5.25 − -4)^(³/₂)]

S = -4π/3 (0.25)^(³/₂) + 4π/3 (9.25)^(³/₂)

S = π/6 [37^(³/₂) − 1]

S ≈ 117.3187

5 0
3 years ago
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