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zimovet [89]
3 years ago
9

Shear strength measurements for spot welds have been found to have standard deviation 1 0 pounds per square inch (psi). If 100 t

est welds are to be measured, what is the approximate probability that the sample mean will be within 1 psi of the true population mean.
Mathematics
1 answer:
Temka [501]3 years ago
5 0

Answer:

P(\mu -1< \bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the Shear strength of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,10)  

Where \mu and \sigma=10

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(\mu,\frac{10}{\sqrt{100}})

We are interested on this probability

P(\mu -1

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\mu -1

=P(\frac{\mu -1-\mu}{\frac{10}{\sqrt{100}}}

And we can find this probability on this way:

P(-1

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1

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