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Elis [28]
3 years ago
13

Please help if you would be so kind, it’s geometry:

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

Step-by-step explanation:

x+(4x-8)+(x+8) = 180

x = 30

∠C = x+8 = 38°

height = 7sin38°

area =0.5·13·7sin38° ≅ 28.0126 cm²

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Find the nth term of this 5 7 9 11 13
NemiM [27]
Firstly, seeing that the sequence is based on odd numbers I would say that this is the formula (which will allow you to know whatever term):

nth term = 2n-1

Hope this helps!
4 0
3 years ago
Read 2 more answers
An engineering scale model shows a church that is 2 inches tall. if the scale is 1 inch = 256 feet, how tall is the actual churc
SVETLANKA909090 [29]

Answer:

Actual height of church = 512 feet

Step-by-step explanation:

Given:

Scale model;

1 inch = 256 feet

Height of church (Scale model) = 2 inches

Find:

Actual height of church

Computation:

Actual height of church = Height of church (Scale model) x scale length

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8 0
3 years ago
Help! It says that I need to determine If both equations represent lines which are parallel, perpendicular, or none...
12345 [234]
    4x + 2y = 8     (1)
    8x + 4y = -4y  (2)

A) Two lines are parallel if they have the same gradient
       - putting both equations into the gradient- intercept form ( y = mx + c                where m is the gradient)
            (1) 4x + 2y = 8
                          2y = 8 - 4x
                            y = -2x + 4
             
            (2) 8x + 4y = -4y
      <span>                    </span>8x = -4y - 4y
                            y = \frac{-8x}{-8}
                            y = -x
   <span>Thus the gradient of the two equations are different and as such          the two lines are not parallel
</span>
B)  When two lines are perpendicular, the product of their gradient is -1
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                                             p = (-2) * (-1)
                                             p =  2
<span>          ∴ the two lines are not perpendicular either.</span>

Thus these lines are SKEWED LINES

4 0
3 years ago
Solve A=p+prt for r.
Furkat [3]

A = p + prt

The above equation can be solved for “r” in such a way.

Subtract “p” from both sides;

A – p = p + prt – p

A – p = prt

Divide both sides by “p” and “t”;

A/pt – p/pt = prt/pt

A/pt – 1/t = r

Or

<span>r =  A/pt – 1/t</span>

3 0
3 years ago
What value of w that makes the equation true 2/3(w+3) = 7
alexdok [17]
The answer is 7.5 or 15/2
3 0
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