2. The Andersons went to dinner at

Factors that influence a hypothesis test with the t statistic Suppose you conduct a hypothesis test about a population mean when

kipiarov [429]

Please find attachment for full question Answer:

1. Stays same

2. Decrease

3. Stays same

4. Decrease

Explanation:

Please find attachment

5 0

3 years ago

Please give me the correct answer.

ololo11 [35]

Answer: Here is the order: 1= 22 2=8 3=56 4=32

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The volume (in cubic meters), vvv, of a rectangular prism is given by the expression: v = a^4-2a^2b^2+b^4v=a 4 −2a 2 b 2 +b 4 v,

zhannawk [14.2K]

Answer:

${a}^{2} - {b}^{2}$

$a - b$

$a + b$

Step-by-step explanation:

The given expression that represents the volume of the rectangular prism is:

$v = {a}^{4} - 2 {a}^{2} {b}^{2} + {b}^{4}$

We can rewrite this to reveal a perfect square pattern.

$v =( { {a}^{2}) }^{2} - 2 {a}^{2} {b}^{2} + ( {b}^{2})^{2}$

We factor using perfect squares to obtain:

$v = ( {a}^{2} - {b}^{2} )^{2}$

$v = ( {a}^{2} - {b}^{2} )( {a}^{2} - {b}^{2} )$

Volume is three dimensional so we need a third factor different from 1.

We further factor one of the difference of two squares to get:

$v = ( {a}^{2} - {b}^{2})(a - b)(a + b)$

So pick the following unique dimensions from the possible answers:

${a}^{2} - {b}^{2}$

$a - b$

$a + b$

6 0

3 years ago

A square building with an area of 225 m2 has a garden surrounding it that has an equal width on all sides. The area of the garde

xenn [34]

Answer:

The width of the garden is 1.16 m

Step-by-step explanation:

step 1

<em>Find the area of the garden</em>

To find out the area of the garden multiply by 1/3 the area of the building

$225(\frac{1}{3})=75\ m^2$

step 2

Find the length side of the square building

The area of a square is

$A=b^2$

where

b is the length side of the square

we have

$A=225\ m^2$

so

$b^2=225\\b=15\ m$

step 3

Find the width of the garden

Let

x ----> the width of the garden

we know that

The area of the building plus the area of the garden is equal to

$(15+2x)^2=225+75$

solve for x

$225+60x+4x^2=225+75\\4x^2+60x-75=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is x=1.16 m

see the attached figure

therefore

The width of the garden is 1.16 m

Find the exact value

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$4x^2+60x-75=0$

so

$a=4\\b=60\\c=-75$

substitute in the formula

$x=\frac{-60\pm\sqrt{60^{2}-4(4)(-75)}} {2(4)}$

$x=\frac{-60\pm\sqrt{4,800}} {8}$

$x=\frac{-60\pm40\sqrt{3}} {8}$

$x=\frac{-60+40\sqrt{3}} {8}\ m$ ----> exact value

8 0

3 years ago

The length of a rectangle is 3 feet more than the width. If the perimeter is 82 feet, what are the length

Tems11 [23]

Answer:

L=22feet

w=19feet

Step-by-step explanation:

Perimeter(p)=82

Length=(L)

Width=(w)

P=2L+2w

2L+2w=82 .......(1)

L-w=3........(11)

From (11) L=3+w

Substitute L=3+w in (1)

2(3+w)+2w=82

Clearing brackets

6+2w+2w=82

6+4w=82

Collect like terms

4w=82-6

4w=76

w=76/4

w=19

Substitute w=19 in (11)

L-19=3

Collect like terms

L=3+19

L=22

8 0

4 years ago