It would be
3.5 × 10⁻³ kg.
The decimal point must be moved 3 places to the right in order to have it behind the first non-zero digit; this gives us the exponent of 3, and since we are moving the decimal to the right, it is a negative exponent.
Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Answer:
here:
1. -9
2. -28
3. 54
4. -100
5. -60
6. -0
7. 49
8. -135
9. -96
10. 300
11. -153
12. -192
THIS TOOK LONG BECAUSE I DID A LONG ONE BUT THEN I MADE IT SHORTER. :D
Answer:
256
Step-by-step explanation:
64*4
(60*4)+(4*4)
240+16
256
you could also take a different approach--
64=4^3
4^3*4=4^4
4^4=16^2=256
