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SIZIF [17.4K]
3 years ago
7

On a road map the distance between two cities is 2.5 in the map scale is 1 inch equals 30 miles what is the actual distance betw

een the cities
Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

98

Step-by-step explanation:

duh

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The YMCA lap pool is a right rectangular prism 36.8\, \text{m}36.8m36, point, 8, start text, m, end text long by 20 \,\text{m}20
PilotLPTM [1.2K]

Volume is a three-dimensional scalar quantity. The depth of the YMCA lap pool is 2 meters.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given that the following details about the YMCA lap pool:

  • The volume of the pool = 1472m³
  • The length of the pool = 36.8m
  • The width of the pool = 20 m

Since the pool is in the space of a right rectangular prism, therefore, the volume of the prism will be the product of length, width and depth. Therefore, the volume of the pool can be written as,

The volume of the pool = Length × width × depth

1472m³ = 36.8m × 20 m × depth of the pool

Depth of the pool = (1472m³ ) / (36.8m × 20m)

                              = 2 meter

Hence, the depth of the YMCA lap pool is 2 meters.

Learn more about Volume here:

brainly.com/question/13338592

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3 0
1 year ago
F(x) = (x - 4)(x + 5)
drek231 [11]

Answer:

x  

2

+x−20

Step-by-step explanation:

6 0
3 years ago
The total number of blocks y is the cube of figure number x
ivanzaharov [21]

Answer:

4;64

5;125

Step-by-step explanation:

Find the cube of the number

E.g. (5x5)x5

=25x5

=125

3 0
2 years ago
Read 2 more answers
Please solve the problem with steps
Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}

The first one: (\frac{1}{2})^{n-1} is a geometric sequence of first term (a_1) "1" and common ratio (r) " \frac{1}{2} ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2

The second one: \frac{1}{6^{n-1}} is a geometric sequence of first term "1", and common ratio (r) " \frac{1}{6} ". Again, since the common ratio is smaller than one, we can find its infinite sum:

Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}

now we simply combine the results making sure we do the indicated difference: Infinite total sum= 2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}

8 0
3 years ago
Read 2 more answers
Please help!<br><br> Find the zeros for y=2x(x+6)(x+-14)
garri49 [273]

Answer:

-6;14

Step-by-step explanation:

x+6=0

x-14=0

4 0
3 years ago
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