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3 years ago

What is 2 5/6 +1 5/7

1 answer:

8 0

Hi Cherise1cherhop lets break this equation down with these steps:

1) add the whole numbers first

2) find the LCD of the fractions and that would be 42 since 42 can go into both denominators through multiplication

3) make the denominators (bottom numbers) the same as the LCD (42)

4) simplify it, now the denominators are equal

5) join the denominators together

6) simplify it (3 + 65/42)

7) convert 65/42 to mixed fraction

8) now that we made it a mixed fraction, simplify it

Answer: 4 23/42

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What equality is shown above

Bogdan [553]

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If you see line broken it's only >

Y>_ - 1/4x+2

Step-by-step explanation:

Starts at 2 on y then next pt go down 1 and 4 to the right

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3 years ago

1. You have three standard decks of cards in front of you. What is the probability of drawing a heart card from all three decks?

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Answer:

1.56%

Step-by-step explanation:

A standard deck of cards has 52 cards, and 13 of these are hearts, as there are 4 suits, and 52/4=13. This means the probability of choosing a heart card from a deck of cards is 1/4, or 25%. Now to find the probability of doing this from 3 decks in a row, we simply cube 1/4 to get 1/64, and in percentage this is ~1.56%.

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3 years ago

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1 year ago

Which number is an integer?<br> -34 -0.4 0.4 3.4 PLS HELP I'M TIMED EDGE 2020

Stella [2.4K]

Answer:

Step-by-step explanation: The four numbers: - 34, -0.4, 0.4, 3.4

so if you look at it it The answer is -34

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3 years ago

Read 2 more answers

A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0

3 years ago