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zavuch27 [327]
3 years ago
10

Can someone explain this differentiation question to me? I can differentiate but then I'm not sure what I am doing

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

note that gradient = \frac{dy}{dx} at x = a

calculate \frac{dy}{dx} for each pair of functions and compare gradient

(a)

\frac{dy}{dx} = 2x and \frac{dy}{dx} = - 1

at x = 4 : gradient = 8 and - 1 : 8 > - 1

(b)

\frac{dy}{dx} = 2x + 3 and \frac{dy}{dx} = - 2

at x = 2 : gradient = 7 and - 2 and 7 > - 2

(c)

\frac{dy}{dx} = 4x + 13 and \frac{dy}{dx} = 2

at x = - 7 : gradient = - 15 and 2 and 2 > - 15

(d)

\frac{dy}{dx} = 6x - 5 and \frac{dy}{dx} = 2x - 2

at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11

(e)

y = √x = x^{\frac{1}{2} }

\frac{dy}{dx} = 1/(2√x) and \frac{dy}{dx} = 2

at x = 9 : gradient = \frac{1}{6} and 2 and 2 > \frac{1}{6}


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