)
<span>tanx = 3/10 </span>
<span>x=16.7 B </span>
<span>2) </span>
<span>tan 64 = 173/x </span>
<span>x = 84.38 D </span>
<span>3) </span>
<span>tan21 = x/442 </span>
<span>x= 169.67 B </span>
<span>4) </span>
<span>tanx = 16.2/48.3 </span>
<span>x = 18.54 A </span>
<span>5) </span>
<span>tanx = 8/6.5 </span>
<span>x = 50.91 C </span>
<span>6) </span>
<span>tan89 = 1149/x </span>
<span>x=20.06 A </span>
<span>7) </span>
<span>tanx = 21/12 </span>
<span>x= 60.26 B </span>
<span>8) B </span>
<span>9) </span>
<span>tanx = 25/63 </span>
<span>x = 21.64 C </span>
<span>10) </span>
<span>tanx = 60/15 </span>
<span>x= 75.96 D</span>
Use algebra for such problems
let, Angle COD = x
Angle KOD = y
Angle KPC = z
Given ,. x - y = 61° ( Equation 1 )
x - z = 53° ( Equation 2 )
Subtract 1st equation from 2nd and you'll get :
z - y = 8° ( Equation 3 )
Now since , x + y + z = 180° ( Equation 4 )
Add Equation 3 to Equation 4 and you'll get
x + 2z = 188° ( Equation 5)
From Equation 2 we know that , x -z = 53°
or, x = 53° + z ( Equation 6 )
Put this value of 'x' in Equation 5 and solve for z. you'll get :
(53° + z) + 2z = 188°
or
3z = 188 - 53 = 135°
solving for z we get
z = 45°
put this value of z in Equation 5
x + ( 2 x 45° ) = 188°
or
x = 188° - 90° = 98°
hence , Angle COD = 98°
F(x)<span>= -10
</span>f(5)=-10
f=-10 divided by 5
f=-2
