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denis-greek [22]
3 years ago
10

Jordan is kayaking upstream. The following equation model his speed: f(x) = 2x2 − 4x − 9, where x is Jordan's speed relative to

land. What is the domain of the function?
x ≥ 1
x ≤ −4
x ≥ −9
All real numbers
Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

All real answers is the correct choice. D.

zhannawk [14.2K]3 years ago
4 0

Answer:

all real numbers .

Step-by-step explanation:

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Mrs. Smith bought 4 dozen doughnuts and paid a total of $13.92. What was the cost of 1 doughout
polet [3.4K]

Answer:

A $0.29

Step-by-step explanation:

4 dozen donuts is 48 donuts. (A dozen is 12 so 4 times 12 is 48). $13.92 divided by 48 is $0.29.

5 0
3 years ago
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Help me will give brainliest!!
faust18 [17]

Answer:

3/4 or 9/12

Step-by-step explanation:

Since there are 12 movies in total. The possible chance of picking a drama movie is a 1 out of 4 chance (3/12 = 1/4), the possible of picking a movie without a drama is a 3 out of 4 chance (9/12 = 3/4)

12/12 - 3/12 = 9/12 = 3/4

3 0
3 years ago
Solve the inequality. Graph the solution on a number line. 7 ≥ t/-2
Elodia [21]

t\geq -14

The graph is shown in the figure attached.

Step-by-step explanation:

We need to solve the inequality 7\geq \frac{t}{-2} and graph the solution.

Solving the inequality: 7\geq \frac{t}{-2}

Switch sides and reverse the inequality:

\frac{t}{-2}\leq 7

Multiplying both sides by -2 and reverse the inequality

-2\frac{t}{-2}\geq 7*-2

t\geq -14

The graph is shown in the figure attached.

Keywords: Graph the inequality

Learn more about Graph the inequality at:

  • brainly.com/question/1626676
  • brainly.com/question/2840217
  • brainly.com/question/6703816

#learnwithBrainly

7 0
3 years ago
What is 99.9999 rounded to the nearest hundredth
Yuki888 [10]
100 would be correct because the 9 in the hundredths place rounds to a ten, and so does every other number.
5 0
4 years ago
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A sledgehammer weighs 18 pounds on Earth and 4 pounds on the planet Namar. 
Advocard [28]
It would weight 18lbs i believe

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3 years ago
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