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3 years ago

Can someone help me with the answer

Mathematics

2 answers:

astra-53 [7]3 years ago

4 0

Answer:

i think 4.356

Step-by-step explanation:

i just multipled them all

velikii [3]3 years ago

3 0

Answer:

1.45

Step-by-step explanation:

hope this helps :)

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Answer:

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3 years ago

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3 years ago

Read 2 more answers

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

Range:

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

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4 years ago

Please help! Write the slope-intercept form equation of the trend line

Eduardwww [97]

Answer:

y= -1/3x+9.2

Step-by-step explanation:

I believe that it is 9.2 although it could be another number in the 9's.

The slope is (rise) -1 and (run) 3 and the line crosses the y-intercept at what it looks like 9.2

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3 years ago

Which of the following describes the following graph?

andre [41]

A. neither a function nor a relation

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3 years ago