Both Euclidean and non-Euclidean geometry have been accepted as valid types of geometry. True or False?

Whats the area of a square that is 9m and 9m? marking branliest.

guapka [62]

Answer:

9 x 9 =81

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Make sure your answer is in

romanna [79]

Answer:

210° , 330°

Step-by-step explanation:

using the sides of the 30- 60- 90 triangle

with legs 1, $\sqrt{3}$ and hypotenuse 2 , then

$sin^{-1}$ $\frac{1}{2}$ = 30° ← related acute angle

since $sin^{-1}$ - $\frac{1}{2}$

then angle is in third / fourth quadrants , then required angles are

180° + 30° = 210° ← in third quadrant

360° - 30° = 330° ← in fourth quadrant

6 0

2 years ago

50 pts!!!! Luciana's laptop has 3,000 pictures. The size of the pictures is skewed to the right, with a mean of 3.7MB and a stan

skelet666 [1.2K]

Answer:

Part A: No, you cannot.

Part B: 0.4491

Explanation:

Part A:

The mean of samples of symmetrical (bell shaped) distributions follow a normal distribution pattern.

Thus, for symmetrical distributions you can use the z-score tables to make calculations that permit calculate probabilities for particular values.

For skewed distributions, in general, the samples do not follow a normal distribution pattern, except that the samples are large.

Since a sample of 20 pictures is not large enough, the answer to this question is negative: you cannot accurately calculate the probability that the mean picture size is more than 3.8MB for an SRS (skewed right sample) of 20 pictures.

Part B.

For large samples, the Central Limit Theorem will let you work with samples from skewed distributions.

Although the distribution of a population is skewed, the Central Limit Theorem states that large samples follow a normal distribution shape.

It is accepted that samples of 30 data is large enough to use the Central Limit Theorem.

Hence, you can use the z-core tables for standard normal distributions to calculate the probabilities for a random sample of 60 pictures instead of 20.

The z-score is calculated with the formula:

z-score = (value - mean/ (standard deviation).

$z=(x-\mu )/\sigma$

Here, mean = 3.7MB, value = 3.8MB, and standard deviation = 0.78MB.

Thus:

$z=(3.7M-3.8MB)/(0.78MB)=-0.128$

Then, you must use the z-score table to find the probability that the z-score is greater than - 0.128.

There are tables that show the cumulative probability in the right end and tables that show the cumulative probability in the left end of a normal standard distribution .

The probability that a z-score is greater than -0.128 is taken directly from a table with the cumulative probability in the left end. It is 0.4491.

4 0

3 years ago

Help please urgent!

myrzilka [38]

Answer:

5

Step-by-step explanation:

8 0

3 years ago

A home security company plans to open a calling center to respond to customer calls and

Romashka-Z-Leto [24]

Answer:

$x+y\geqslant 12$

$x+2y\leqslant 20$

Step-by-step explanation:

Inequalities

The home security company will choose between two options for cubicles: the small cubicle for only one operator and the large cubicle to hold 2 operators. Let x be the number of small cubicles and y the number of large cubicles. Since each small cubicle has 49 square feet, the total area occupied by them will be 49x. Each large cubicle occupies 80 square feet, so the y cubicles use 80y square feet. The total area used by them is

Area=49x+80y

Assuming there is no operator without cubicle and all cubicles are fully occupied, the number of operators will be

Operators=1x+2y=x+2y

The number of cubicles is

# cubicles=x+y

The conditions of the problem state that

$x+y\geqslant 12$

$x+2y\leqslant 20$

7 0

3 years ago