Answer:
A. 13 boxes
B. $18.00
C. $3.60
D. 0.30
Step-by-step explanation:
6 boxes = 21.60
that is 3.60 per box
A. 50.00/3.60 = 13.88 so he can purchase 13 boxes
B. 1 box is 12 ounces
60/12 = 5 boxes needed for 60 ounces. 5 x 3.60 = 18
C. One box is 3.60
D. 3.60/12 = 0.30 per ounce
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Y = -(1/2)x + 4
y + (1/2)x =4
(1/2)x + y = 4
Multiply both sides by 2
2*(1/2)x + 2*y = 2*4
x + 2y = 8
Option B.
Answer:
Step-by-step explanation:
Answer:
x = -2
x = 8
Step-by-step explanation:
Excluded values are the ones which make the denominator zero
3x² + x - 10
3x² + 6x - 5x - 10
3x(x + 2) - 5(x + 2)
(x + 2)(3x - 5)
x² - 6x - 16
x² - 8x + 2x - 16
x(x - 8) + 2(x - 8)
(x - 8)(x + 2)
[(x + 2)(3x - 5)] ÷ [(x - 8)(x + 2)]
(3x - 5)/(x - 8)
So excluded values are 8, -2
