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k0ka [10]
3 years ago
7

Find the length of segment KL in the trapezoid shown.

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0
KLMN is the trapezoid. So:( KL + MN ) / 2 = HJ( 4 x + 1 + 27 ) / 2 =  5 x + 2    / * 24 x + 28 = 10 x + 410 x - 4 x = 28 - 46 x = 24x = 24 : 6x = 4KL = 4 * 4 + 1 = 16 + 1 = 17Answer: KL = 17

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A box with a square base and open top must have a volume of 237276 cm^3. We wish to find the dimensions of the box that minimize
svp [43]

Answer:

A(x)=\dfrac{x^3+949104}{x}

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 237276 cubic centimetre. We want to find a formula for the surface area of the box in terms of only x, the length of one side of the square base.

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume,

V=x^2h=237276\\\\h=\dfrac{237276}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

Area, A(x,h)=x^2+4xh

Substitute h derived above into A(x,h)

Area=x^2+4x(\frac{237276}{x^2})\\\\A(x)=x^2+\dfrac{949104}{x}\\\\A(x)=\dfrac{x^3+949104}{x}

Therefore, a formula for the surface area of the box in terms of only x, the length of one side of the square base is:

A(x)=\dfrac{x^3+949104}{x}

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vampirchik [111]

Answer:

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