All categories

3 years ago

A bag of marbles has 5 blue marbles, 3 red marbles, and 6 yellow marbles. A marble is drawn from the bag at

Mathematics

2 answers:

irina [24]3 years ago

8 0

A14nswer:

Step-by-step explanation:

zysi [14]3 years ago

5 0

Answer:

i dont know ????

Step-by-step explanation:

You might be interested in

Compare and contrast expressions equations and inequalities

babymother [125]

Equations can have one solution, but inequalities have infinite solutions.

Hope this helps!

4 0

3 years ago

Please give real answers with an explaination. I will follow + I will give the brainliest. No Docs/No Files/No Links, only answe

Rufina [12.5K]

Answer:

134

Step-by-step explanation:

the line where B and X are equal to 180 so you subtract 180 from B witch is 134

6 0

3 years ago

While watching a football game, Jordan decided to list yardage gained as positive integers and yardage lost as negative integers

koban [17]

Answer:

There is a loss of 2 yards.

Step-by-step explanation:

To find the overall gain or loss, we add or subtract there values.

Initially, we have 0 yards.

Records 14, so 0 + 14 = 14, that is, for now a gain of 14

Then loses 7, so 14 - 7 = 7, for now a gain of 7.

Then, 7 - 9 = - 2, so in all, there is a loss of 2 yards.

3 0

3 years ago

8x + y = 20<br> x - 2y = -6

OleMash [197]

Answer: the answer is

Step-by-step explanation:

6 0

2 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

3 0

2 years ago