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3 years ago

The clockwise distance between North east and south west is

Mathematics

1 answer:

andrezito [222]3 years ago

5 0

<h2>Answer :</h2>

Say it is two o'clock, draw an imaginary line between the hour hand and twelve o'clock to create the north-south line. You know the sun rises in the east and sets in the west so this will tell you which way is north and which way south. If you are in the Southern Hemisphere then it will be the other way round.

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If x+2=9 what is x ?

Romashka-Z-Leto [24]

X=7 because you just subtract 2 from 9 and you get 7 for x

7 0

3 years ago

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t^2+4t+4 t^2-2t+1 Consider the parametric curve a. Find points on the parametric curve where the tangent lines are vertical. b.

kondaur [170]

Answer:

a) $t = 1$ , b) $t = -2$ , c) Concave upward: $(-\infty, 1)$ . No intervals being concave downward.

Step-by-step explanation:

a) Tangent line is vertical if slope is undefined, whose points are associated with discontinuities of the function. Rational functions have discontinuities associated with the denominator:

$f(t) = \frac{t^{2}+4\cdot t +4}{t^{2}-2\cdot t + 1}$

By factorizing each component, the function is re-arranged as:

$f(t) = \frac{(t+2)^{2}}{(t-1)^{2}}$

There is no avoidable discontinuities. The only point where tangent line is vertical is $t = 1$ .

b) Tangent line is horizontal if slope is equal to zero, whose point is associated to the points that makes function equal to zero. Rational functions have horizontal tangent lines if numerator is equal to zero and denominator is different to zero. Hence, the only point where tangent line is horizontal is $t = -2$ .

c) An interval is concave upward if exist an absolute minimum inside, which can be found by the help of the First and Second Derivative Tests.

$f'(t) = \frac{2\cdot (t+2)\cdot (t-1)^{2}-2\cdot (t-1)\cdot (t+2)^{2}}{(t-1)^{4}}$

$f'(t) = 2\cdot (t+2)\cdot (t-1)\cdot \left[\frac{t-1-t-2}{(t-1)^{4}}\right]$

$f'(t) = -\frac{6\cdot (t+2)\cdot (t-1)}{(t-1)^{4}}$

$f'(t) = -\frac{6\cdot (t+2)}{(t-1)^{3}}$

The only critical point is:

$-6\cdot (t+2) = 0$

$t = -2$ (which coincides with the result of point b)

$f''(t) = -6\cdot \left[\frac{(t-1)^{3}-3\cdot (t-1)^{2}\cdot (t+2)}{(t-1)^{6}}\right]$

$f''(t) = -6\cdot \left[\frac{1}{(t-1)^{3}}-\frac{3\cdot (t+2)}{(t-1)^{4}} \right]$

The value associated with the critical point is:

$f''(-2) = \frac{2}{9}$

Which means that critical point is an absolute minimum, and, consequently, the interval that is concave upward is $(-\infty, 1)$ . There is no absolute maximums and, therefore, there is no interval that is concave downward.

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4 years ago

What is the decimal version of 28/80*

Maurinko [17]

Answer:

0.35

Step-by-step explanation:

7 0

3 years ago

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Here are five number cards.

marta [7]

Possible ways to get >32:
19 , 14
14, 19
18,22
22, 19
13,22
22,13
14, 22
22,14

That is 8 ways
Total number of permutations of 2 cards from 5
= 5P2
= 5!/3!
= 20
So required probability
= 8/20
= 2/5.

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2 years ago

The ratios of the angles in ABC is 3:5:7. Find the

Kazeer [188]

So you have a diagram or picture of the triangle?

Anyways...

Answer: 36

Explanation:

3:5:7 is the ratio of the triangle's angles

The sum of all angles = 180 degrees.

3 + 5 + 7 = 15

Lets assume 'a' is the smallest angle with the ratio of 3

b is the second largest with a ratio of 5

And c is the largest angle with the ratio of 7

In other words:

a + b + c = 180

For 15 to get to 180 => 180 ÷ 15 = 12

So 15 × 12 = 180

So for 3 to get to a => 3 × 12 = 36

Thus the smallest angle is 36 degrees

8 0

3 years ago

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The clockwise distance between North east and south west is ​

The clockwise distance between North east and south west is