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marta [7]
3 years ago
10

Here is a balanced hanger:

Mathematics
1 answer:
Slav-nsk [51]3 years ago
3 0

I don't know exactly i think its either 3 grams or 7 grams or 2 1/2 grams

sorry if its wrong

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I need help!please help me
natali 33 [55]

Answer:

its four of them

Step-by-step explanation:

add one to each one

6 0
3 years ago
Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44 chickens and 36 ducks for
STALIN [3.7K]
Answer: chicken $8, duck $5

Explanation:

x - the cost of a chicken
y - the cost of a duck

he sold 50 chickens and 30 ducks for $550: 50x + 30y = 550
he sold 44 chickens and 36 ducks for $532: 44x + 36y = 532

50x + 30y = 550                divide by 10
44x + 36y = 550                 divide by 4
______________
50x/10 + 30y/10 = 550/10
44x/4 + 36y/4 = 532/4
______________
5x + 3y = 55                                    
Multiply by (-3)
11x + 9y = 133
______________
5x * (-3) + 3y * (-3) = 55 * (-3)
11x + 9y = 133
______________
-15x - 9y = -165
11x + 9y = 133
______________
Sum up:
-4x + 0y = -32
-4x = -32
x = -32/-4
x = 8

Since 5x + 3y = 55  and x = 8, then:
5 * 8 + 3y = 55
40 + 3y = 55
3y = 55 - 40
3y = 15
y = 15/3
y = 5
6 0
3 years ago
Read 2 more answers
What is the total surface area of a cylindrical tank having
UkoKoshka [18]

Answer:

Could be C) or D) None of these, 29688.05cm^2

Step-by-step explanation:

Did the question to round off to any numbers?

Formula for cylinder's T.S.A: 2 π r h + 2 π r^2

Diameter= 2 x radius

Radius = 70cm / 2 = 35cm

Height -> need to convert m to cm -> 100cm

Substitute these values into the formula:

2 x π  x 35 x 100 + 2 x π x (35)^2 = 29688.05cm^2

8 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
I need help on this.
andrew11 [14]

To find the midpoint, add x1 and x2 then divide by 2, then add y1 and y2 and divide by 2.


Midpoint = (2a +2b /2 , 0 + 2c /2)


Midpoint = a+b, c


3 0
2 years ago
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