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Sphinxa [80]
3 years ago
15

The radius of a circle is 7m , find its area in terms of π

Mathematics
2 answers:
dangina [55]3 years ago
8 0

Answer:

49π

Step-by-step explanation:

A = π r^{2}

A = π 7^{2}

A = 49π

For the one you put in the comment...

The radius of a circle is 19cm find its area in terms of π

A = π r^{2}

A = π 19^{2}

A = 361π

For the other one you put in the comment

The radius of a circle is 4 cm find its area in terms of π

A = π r^{2}

A = π 4^{2}

A = 16π

For the other one you put in the comment

The radius of a circle is 20 cm find its area in terms of π

A = π r^{2}

A = π 20^{2}

A = 400π

Hope this helped!

Have a supercalifragilisticexpialidocious day!

viktelen [127]3 years ago
3 0

HOPE THIS HELPS

CAN U PLEASE GIVE ME BRAINLIEST

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Evaluate 4.8 divided by 0.08
ArbitrLikvidat [17]

Answer:

60,

Step-by-step explanation:

4.8 / 0.08    

Removing the decimal points by multiplying by 100:

= 480 / 8

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3 years ago
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Solve [(x+7) x 3-5] / 4 = 7<br> What is the first step in this equation
Nitella [24]

Answer:

The first step is to slove the numbers in the brackets

Step-by-step explanation:

[(x+7) x -2] / 4 = 7

-2(x+7) / 4 = 7

-2x-14 / 4 = 7

-2x-14 = 28

-2x = 42

x = -21

PEMDAS

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2 years ago
Isosceles JAM has convex angle M. JM=35,MA=4n+3, angle J=14w-1, and angle m=98 Find n. Find w. Find the perimeter of JAM
Lena [83]

Answer:

n = 8, w = 3 and perimeter = 122.83 units.

Step-by-step explanation:

Let the angle M is the angle between the equal sides of isosceles JAM.

So, JM = MA

⇒ 35 = 4n + 3

⇒ 4n = 32

⇒ n = 8 (Answer)

Now, if ∠ J = 14w - 1 and ∠ M = 98°, then

2(14w - 1) + 98 = 180

⇒ 2(14w - 1) = 82

⇒ 14w - 1 = 41

⇒ w = 3 (Answer)

Now, draw a perpendicular bisector on JA from vertex M and it meets JA at P say.

So, Δ MPJ will be a right triangle with ∠ J = (14w - 1) = 41° {Since w = 3}

Hence, \cos 41 = \frac{JP}{JM} = \frac{JP}{35}

⇒ JP = 35 cos 41 = 26.415

So, JA = 2 × JP = 52.83  

So, the perimeter of Δ JAM is = 35 × 2 + 52.83 = 122.83 units (Answer)

4 0
3 years ago
If f(x) = x + 7 and g(x) = 1 / x - 13, whaf is the domain of (f°g)(x)?​
ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of (f \circ g)(x) = f(g(x)) is the same as the domain of g(x)

The domain for g(x) is \{x|x \ne 13\} saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0
3 years ago
-12p^2 - 27p +27 = 0
EleoNora [17]

Answer:

that's the right answer

Step-by-step explanation:

6 0
3 years ago
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