2L+2W=157.5
L=W-30
2(W-30)+2W=157.5
2W-60+2W=157.5
+60 +60
4w=217.5
W=54.4(.37 rounded to nearest tenth)
L=24.4
Answer:
43.531
Step-by-step explanation:
This problem needs the law of cosines since the three sides of the triangle are involved as well as one angle. The law of cosines is:
c^2 = a^2 + b^2 - 2ab*cos(C)
Where the lowercase letters are side values and capital letters are angle values. Just in case I will mention side a is the one with a length of 14, side b is 20 and c = 12.
Since it is asking for angle A instead of angle C we can rewrite the law of cosines to fit that, basically just rearranging the letters.
a^2 = c^2 + b^2 - 2cb*cos(A)
Now we just plug in and solve.
14^2 = 12^2 + 20^2 - 2*12*20*cos(A)
Rearrange to get A by itself
![\frac{14^2-12^2-20^2}{-2*12*20}=cos(A)](https://tex.z-dn.net/?f=%5Cfrac%7B14%5E2-12%5E2-20%5E2%7D%7B-2%2A12%2A20%7D%3Dcos%28A%29)
Now we take the inverse cosine, or arccos of both sides to get our answer.
![arccos(\frac{14^2-12^2-20^2}{-2*12*20})=A](https://tex.z-dn.net/?f=arccos%28%5Cfrac%7B14%5E2-12%5E2-20%5E2%7D%7B-2%2A12%2A20%7D%29%3DA)
Let me know if there is something in my explanation you don't understand.
Answer:
assosative of multiplcation
Step-by-step explanation:
Answer: x^6 or x to the power of 6
Step-by-step explanation:
Not really sure what the expressions are but I just simplified the expression.
You would use the distributive property on each side of the equation