Answer:
If you input a value of x then we get the output f(x) = y, which is the function of x. This is a function of x. Hence, x² = y is a function of x.
Step-by-step explanation:
1) Slope tell about the steepness of the line.
To find slope we look at the rise and run between 2 points.
attached the graph of line with slope
slope = 
= 
So slope = 2
2) we have x and y intercepts
x intercept is the point where the line crosses x axis
x intercept at x= 3
y intercept is the point where the line crosses y axis
y intercept at y= 6
3) Linear equation is y= 3x+2
function is f(x) = 3x+2
We can graph it using slope and y intercept
In f(x)= 3x + 2 , slope =3 and y intercept = 2
slope = 3, rise = 3 and run =1
The graph of f(x)= 3x+2 is attached below.
Answer:
80 feet
Step-by-step explanation:
Given:
Initial speed of the car (
) = 40 ft/sec
Deceleration of the car (
) = -10 ft/sec²
Final speed of the car (
) = 0 ft/sec
Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.
Now, deceleration means rate of decrease of velocity.
So, 
Negative sign means the velocity is decreasing with time.
Now,
using chain rule of differentiation. Therefore,

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,
![\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_%7B40%7D%20%7Bv%7D%20%5C%2C%20dv%3D%5Cint%5Climits%5Ex_0%20%7B-10%7D%20%5C%2C%20dx%5C%5C%5C%5C%5Cleft%20%5B%20%5Cfrac%7Bv%5E2%7D%7B2%7D%20%5Cright%20%5D_%7B40%7D%5E%7B0%7D%3D-10x%5C%5C%5C%5C-10x%3D%5Cfrac%7B0%7D%7B2%7D-%5Cfrac%7B1600%7D%7B2%7D%5C%5C%5C%5C10x%3D800%5C%5C%5C%5Cx%3D%5Cfrac%7B800%7D%7B10%7D%3D80%5C%20ft)
Therefore, the car travels a distance of 80 feet before stopping.
It is closer to 1 hope i helped
Answer:
x = -2
Step-by-step explanation:
7x -6y = -20
y=1
7x - 6 = -20
7x = -14
x = -2