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jeyben [28]
3 years ago
13

Two young sumo wrestlers decided to go on a special diet to gain weight rapidly. They each gained weight at a constant rate.

Mathematics
1 answer:
KatRina [158]3 years ago
8 0
Gskwkwbsnakqcaahbdnakabsbzhz
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HELP I NEED HELP ASAP
Irina18 [472]

Answer:

Step-by-step explanation:

5 0
2 years ago
Divide. (–6m 7 + 20m 6) ÷ 2m 4 A. –3m 3 + 20m 6 B. –3m 3 + 10m 2 C. –6m 7 + 20m 2 D. –3m 7 + 10m 6 Reset Selection
allsm [11]
 ( –6m^7 + 20m^6<span>) ÷ 2m^4 = ???

as you know

</span> –6m^7 + 20m^6 = 2m^4 (-3m^3 + 10m^2)

[2m^4 (-3m^3 + 10m^2) ] / 2m^4 (2m^4 is canceled out)

= -3m^3 + 10m^2

answer is B. –3m^3 + 10m^2
6 0
3 years ago
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Pls helpppppppp!!!!!!!!!!!!!!!!!!!!<br><br>I'll award brainliest
kolezko [41]

Answer:

I swear i had the exact same problem

Step-by-step explanation:

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6 0
3 years ago
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Please help to find an explicit formula for calculating the sum Mn
defon

The explicit formula for calculating the sum is

S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}

The sum of the nth term of a sequence is expressed as;

S_n=\frac{n}{2}(2a+(n-1)d)

a is the first term

d is the common difference

n is the number of terms

For the sequence  0 + 1 + 2 + 3  +...

S_n=\frac{n}{2}(2(0)+(n-1)1)\\S_n= \frac{n}{2}(n-1)\\S_n= \frac{n(n-1)}{2}

Similarly for the sequence:

1 + 2+ 3 + 4+...

S_n=\frac{n}{2}(2(1)+(n-1)1)\\S_n= \frac{n}{2}(2+n-1)\\S_n= \frac{n(n+1)}{2}

Taking the product of the sum to get the explicit formula for calculating the sum

S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}

Learn more here: brainly.com/question/24547297

8 0
2 years ago
|2+3(-4)|
puteri [66]

Answer:

10

Step-by-step explanation:

So we have the expression:

|2+3(-4)|

First, evaluate within the absolute value bars. 3 times -4 is -12. Thus:

=|2-12|

Now, subtract:

=|-10|

The absolute value of -10 is positive 10. So:

=10

And we're done!

3 0
3 years ago
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