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3 years ago

7

The function f(x) = 2·5x can be used to represent the curve through the points (1, 10), (2, 50), and (3, 250). What is the multi

plicative rate of change of the function?
2
5
10
32

2 answers:

Marysya12 [62]3 years ago

7 0

Answer:

B

Step-by-step explanation:

Talja [164]3 years ago

4 0

Answer:

its B. 5 . on e d g e n u i t y

Step-by-step explanation:

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A survey of shoppers is planned to determine what percentage use credit cards. prior surveys suggest 63% of shoppers use credit

Alona [7]

We would need a sample size of 560.

We first calculate the z-score associated. with this level of confidence:
Convert 95% to a decimal: 95% = 95/100 = 0.95
Subtract from 1: 1-0.95 = 0.05
Divide by 2: 0.05/2 = 0.025
Subtract from 1: 1-0.025 = 0.975

Using a z-table (http://www.z-table.com) we see that this is associated with a z-score of 1.96.

The margin of error, ME, is given by:
$ME=z*\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

We want ME to be 4%; 4% = 4/100 = 0.04. Substituting this into our equation, as well as our proportion and z-score,
$0.04=1.96\sqrt{\frac{0.63(1-0.63)}{n}}
\\
\\\text{Dividing both sides by 1.96,}
\\
\\\frac{0.04}{1.96}=\sqrt{\frac{0.63(0.37)}{n}}
\\
\\\text{Squaring both sides,}
\\
\\(\frac{0.04}{1.96})^2=\frac{0.63(0.37)}{n}
\\
\\\text{Multiplying both sides by n,}
\\
\\n(\frac{0.04}{1.96})^2=0.63(0.37)
\\
\\n(\frac{0.04}{1.96})^2=0.2331
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\\\text{Isolating n,}
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\\n=\frac{0.2331}{(\frac{0.04}{1.96})^2}=559.67\approx560$

3 0

3 years ago

Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0

IrinaK [193]

We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: $36 y^{2} =( x^{2} -4)^3$
We divide by 36 and take the root of both sides to obtain: $y = \sqrt{ \frac{( x^{2} -4)^3}{36} }$

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: $y = \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}$

Let's leave that for the moment and look at the formula for arc length. The formula is $L= \int\limits^c_d {ds}$ where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: $ds= \sqrt{1+( \frac{dy}{dx})^2 } dx$

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here $x^2-4$ ). More formally, we can let $u=x^{2} -4$ and then consider the derivative of $u^{3/2}du$ . Either way, we obtain,

$\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}$

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
$( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}$

This means that in our case:
$ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx$
$ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx$
$ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx$
$ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx$
$ds= \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx$

Recall, the formula for arc length: $L= \int\limits^c_d {ds}$
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

$L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x$ evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, $[(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}$

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3 years ago

What is the answer 6a+5a-b-5b+2a

notsponge [240]

Answer: 13a-6b

Step-by-step explanation:

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Lana71 [14]

The answer to your question is b. Hope i helped :)

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