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Sidana [21]
3 years ago
12

Please help, show work! Limits and functions! 85 points!

Mathematics
1 answer:
swat323 years ago
3 0

Answer:

Ok I might misunderstand this but this is what I got ( in order )

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Parentheses are placed differently in each of the following expressions. Drag the tiles to match the correct
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3 years ago
36 out of 100 randomly selected taxpayers knew about tax incentives for installing energy-saving furnaces. Find a 90% confidence
tresset_1 [31]

Answer:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, \pi = \frac{36}{60} = 0.6

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.28

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.44

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

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4 years ago
Please help! Will give brainlist
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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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Find the 20th term of an A.P whose first term is 102 and common difference -3
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A(20) = a+(20-1)d

A(20) = 102+(19)(-3)

A(20) = 102-57 = 45

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4 years ago
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